If a monkey drops a banana off of a cliff, where are the potential and kinetic energies of the banana equal.(1 point) Responses
half way down
at the bottom
a quarter of the way down
at the top
To determine where the potential and kinetic energies of the banana are equal when it is dropped off a cliff, you can apply the law of conservation of energy.
The potential energy of an object is given by the equation PE = mgh, where m represents the mass of the object, g is the gravitational acceleration (approximately 9.8 m/s^2 on Earth), and h is the height of the object above a reference point.
The kinetic energy of an object is given by the equation KE = 0.5mv^2, where m represents the mass of the object and v is its velocity.
When the monkey drops the banana, it starts from rest at the top of the cliff, so its initial velocity is zero. As it falls, the potential energy due to its height decreases, and the kinetic energy increases.
As the banana falls, its potential energy is gradually converted into kinetic energy. At a certain point, the potential energy and kinetic energy are equal. This occurs when half of the initial potential energy is converted into kinetic energy.
Therefore, the potential and kinetic energies of the banana are equal halfway down the cliff.