A fryer consumes an amount of electrical energy of 4400 kJ in 30 minutes. In 5 minutes, it provides a quantity of thermal energy of 0.125 kWh. Calculate the efficiency of the device.
To calculate the efficiency of the fryer, we need to find the ratio of the useful output energy (thermal energy) to the energy input (electrical energy).
First, let's convert the thermal energy provided in 5 minutes to kilojoules (kJ):
0.125 kWh = 0.125 * 1000 Wh = 125 Wh
1 Wh = 3600 J
125 Wh = 125 * 3600 J = 450000 J = 450 kJ
So, in 5 minutes, the fryer provides a thermal energy of 450 kJ.
Now we can calculate the efficiency:
Efficiency = (Useful Output Energy / Energy Input) * 100%
= (450 kJ / 4400 kJ) * 100%
= (0.1023) * 100%
= 10.23%
Therefore, the efficiency of the fryer is approximately 10.23%.
To calculate the efficiency of the fryer, we need to compare the amount of useful output energy (thermal energy) to the amount of input energy (electrical energy).
First, let's convert the given values to a consistent unit. Since both kilojoules (kJ) and kilowatt-hours (kWh) are used, we need to convert one to match the other. Let's convert the thermal energy from kilowatt-hours to kilojoules:
0.125 kWh = 0.125 × 1000 Wh = 125 Wh
1 kWh = 1000 Wh
125 Wh = 125 × 3600 J = 450000 J = 450 kJ
Now we can calculate the efficiency using the following formula:
Efficiency = (Useful output energy / Input energy) × 100%
Efficiency = (450 kJ / 4400 kJ) × 100%
Efficiency = (450 / 4400) × 100%
Efficiency = 0.1023 × 100%
Efficiency ≈ 10.23%
Therefore, the efficiency of the fryer is approximately 10.23%.
To calculate the efficiency of the fryer, we need to calculate the ratio of the useful output energy (thermal energy) to the input energy (electrical energy).
First, let's convert the given quantities to the same units:
1 kWh = 3600 kJ
The thermal energy provided by the fryer in 5 minutes is 0.125 kWh. Converting this to kilojoules:
0.125 kWh * 3600 kJ/kWh = 450 kJ
Now we have the useful output energy.
Next, we need to calculate the input energy. The fryer consumes 4400 kJ in 30 minutes. To find the input energy consumed in 5 minutes, we can use the proportion:
4400 kJ / 30 min = X kJ / 5 min
Cross-multiplying:
5 min * 4400 kJ = 30 min * X kJ
X = (5 min * 4400 kJ) / 30 min
X = 733.333 kJ
Now we have the input energy.
Finally, we can calculate the efficiency using the formula:
Efficiency = (useful output energy / input energy) * 100%
Efficiency = (450 kJ / 733.333 kJ) * 100%
Efficiency ≈ 61.34%
So, the efficiency of the fryer is approximately 61.34%.