A mountain goat is climbing to the top of a large cliff. the cliff is 50 feet higher than its starting point. if it takes the goat 22 minutes to climb this cliff, interpret the quotient to describe the rate of change in the goat’s elevation. give your answer to the nearest hundredth.(1 point) the quotient that best represents the rate of change in the goat’s elevation is ______ feet/minute.
To find the rate of change in the goat's elevation, we divide the change in elevation (50 feet) by the time taken (22 minutes).
Rate of change = change in elevation / time taken
= 50 feet / 22 minutes
To give the answer to the nearest hundredth, we divide 50 by 22 and round to the nearest hundredth:
Rate of change = 50 / 22 ≈ 2.27
The quotient that best represents the rate of change in the goat's elevation is 2.27 feet/minute.
A bird is flying at an average altitude of 10 meters above the ground. after 3 seconds, it settles on a branch that is 3 meters above the ground. interpret the quotient to describe the rate of change in the bird’s altitude. give your answer to the nearest hundredth and remember that the bird is descending.(1 point) the quotient that best represents the rate of change in the bird’s altitude is
_______ meters/second.
To find the rate of change in the bird's altitude, we divide the change in altitude (10 - 3 = 7 meters) by the time taken (3 seconds).
Rate of change = change in altitude / time taken
= 7 meters / 3 seconds
To give the answer to the nearest hundredth, we divide 7 by 3 and round to the nearest hundredth:
Rate of change = 7 / 3 ≈ 2.33
The quotient that best represents the rate of change in the bird's altitude is 2.33 meters/second.
A whale is swimming at a current depth of 15 meters below the surface. it swims up toward the surface and arrives there 9.5 seconds later. find the quotient that best describes the rate of change in the whale’s depth. give your answer to the nearest hundredth.(1 point) the quotient that best represents the rate of change in the whale’s depth is _____ meters/second.
To find the rate of change in the whale's depth, we divide the change in depth (15 meters) by the time taken (9.5 seconds).
Rate of change = change in depth / time taken
= 15 meters / 9.5 seconds
To give the answer to the nearest hundredth, we divide 15 by 9.5 and round to the nearest hundredth:
Rate of change = 15 / 9.5 ≈ 1.58
The quotient that best represents the rate of change in the whale's depth is 1.58 meters/second.
Solve using division of rational numbers. if a car’s value decreases by $2,500 in the first 6 months, how much does the value decrease per month? (round to the nearest
hundredth.) (1 point)
-$ _____
To find out how much the car's value decreases per month, we divide the decrease in value ($2,500) by the number of months (6).
Value decrease per month = decrease in value / number of months
= $2,500 / 6
To give the answer to the nearest hundredth, we divide 2,500 by 6 and round to the nearest hundredth:
Value decrease per month = $2,500 / 6 ≈ -$416.67
The car's value decreases approximately by $416.67 per month. Note that the negative sign denotes a decrease in value.
A restaurant uses a 15-pound bag of flour in 4 days. each day, the bag of flour gets lighter as more flour is used. how much does the average amount of flour in the bag change each day? (round to the nearest hundredth.) (1 point)
____ pounds
To find the average amount of flour the bag changes each day, we divide the total change in the bag's weight (15 pounds) by the number of days (4).
Average change per day = total change / number of days
= 15 pounds / 4
To give the answer to the nearest hundredth, we divide 15 by 4 and round to the nearest hundredth:
Average change per day = 15 / 4 ≈ 3.75
Therefore, the average amount of flour in the bag changes by approximately 3.75 pounds each day.
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. the squirrel starts on a perch 100 feet above the ground. the squirrel moves from the perch down to its stored acorns in 5.25 seconds. interpret the quotient to describe the rate of change in the squirrel’s height above the ground. give your answer to the nearest hundredth.(1 point)
responses the quotient that describes the rate of change in the squirrel’s height above the ground is −19.05 feet/second.
the quotient that describes the rate of change in the squirrel’s height above the ground is 19.05 feet/second.
the quotient that describes the rate of change in the squirrel’s height above the ground is 10.48 feet/second.
the quotient that describes the rate of change in the squirrel’s height above the ground is −10.48 feet/second.