A water tank decreases by 10 gallons every 3 hours every day . What is the total change in the amount of water in the tank after 6 days?
In one day, which is 24 hours, the water tank will decrease by 10 gallons/3 hours * 8 hours = <<10/3*8=26.666666666666668>>26.67 gallons.
So the total change in the amount of water in the tank for 6 days would be 6 days * 26.67 gallons/day = <<6*26.67=160.02>>160.02 gallons. Answer: \boxed{160}.
To find the total change in the amount of water in the tank after 6 days, we first need to calculate the change per day and then multiply it by the number of days.
Given that the water tank decreases by 10 gallons every 3 hours every day, we can find the change per day by dividing 10 gallons by 3 hours and then multiplying it by 24 hours:
Change per day = (10 gallons / 3 hours) * 24 hours = 80 gallons
Now, we can multiply the change per day by the number of days:
Total change = Change per day * Number of days = 80 gallons/day * 6 days = 480 gallons
Therefore, the total change in the amount of water in the tank after 6 days is 480 gallons.
To find the total change in the amount of water in the tank after 6 days, we need to calculate the change in 10-gallon intervals for each day and then sum up those changes.
First, let's determine the number of 10-gallon intervals in 6 days. Since the water tank decreases by 10 gallons every 3 hours, we convert 6 days to hours: 6 days * 24 hours/day = 144 hours.
Next, we find the number of 10-gallon intervals that occur in 144 hours: 144 hours / 3 hours/interval = 48 intervals.
Therefore, the water tank will experience 48 intervals of 10-gallon decrease in 6 days.
Finally, we multiply the number of intervals by the amount of change in each interval to find the total change in the amount of water: 48 intervals * 10 gallons/interval = 480 gallons.
So, the total change in the amount of water in the tank after 6 days is 480 gallons.