Mrs. Jennings wants to take her class on a field trip to the museum. The bus will cost a total of $100, and the museum will charge $2 per student. The museum does not charge teachers for admission. What is the maximum number of students that Mrs. Jennings can take to the museum without exceeding her budget of $150?
Let's call the maximum number of students Mrs. Jennings can take to the museum x.
The cost of the bus is $100, so Mrs. Jennings will have $150 - $100 = $<<150-100=50>>50 left to spend on student tickets.
Each student ticket costs $2, so the maximum number of student tickets Mrs. Jennings can buy is $50 / $2 = <<50/2=25>>25.
Therefore, the maximum number of students that Mrs. Jennings can take to the museum without exceeding her budget is x = 25 students. Answer: \boxed{25}.
To find the maximum number of students Mrs. Jennings can take to the museum without exceeding her budget of $150, we need to subtract the cost of the bus from her budget and then divide the remaining budget by the cost per student.
Step 1: Subtract the cost of the bus from the budget:
Budget - Cost of the bus = $150 - $100 = $50
Step 2: Divide the remaining budget by the cost per student:
Remaining budget / Cost per student = $50 / $2 = 25
Therefore, Mrs. Jennings can take a maximum of 25 students to the museum without exceeding her budget of $150.
To determine the maximum number of students that Mrs. Jennings can take to the museum without exceeding her budget, we need to consider the costs of the bus and the admission fees for the students.
Let's break down the costs:
1. Bus cost: $100
2. Museum admission fee per student: $2
3. Budget constraint: $150
To find the maximum number of students, we'll subtract the bus cost from the total budget and then divide the remaining amount by the cost per student:
Total budget - Bus cost = Remaining budget
Remaining budget ÷ Admission fee per student = Maximum number of students
Applying this formula to the given information:
$150 (total budget) - $100 (bus cost) = $50 (remaining budget)
$50 (remaining budget) ÷ $2 (admission fee per student) = 25 (maximum number of students)
Therefore, Mrs. Jennings can take a maximum of 25 students to the museum without exceeding her budget of $150.