What is the mass of calcium hydroxide that will react with 21.4g of ammonium chloride according to the following equation
2NH4 Cl + Ca(OH)2—> 2NH3+CaCl2 +2H2O
To find the mass of calcium hydroxide that will react with 21.4g of ammonium chloride, we need to use the stoichiometry of the balanced equation.
From the balanced equation, we can see that the coefficient of ammonium chloride (NH4Cl) is 2, and the coefficient of calcium hydroxide (Ca(OH)2) is 1. This means that 2 moles of NH4Cl react with 1 mole of Ca(OH)2.
First, let's convert the mass of ammonium chloride (NH4Cl) to moles:
Mass of NH4Cl = 21.4g
Molar mass of NH4Cl = 14.01g/mol (N) + 4(1.01g/mol)(H) + 1(35.45g/mol) (Cl)
= 53.49g/mol
Number of moles of NH4Cl = mass / molar mass
= 21.4g / 53.49g/mol
≈ 0.3995 mol
Since the ratio of NH4Cl to Ca(OH)2 is 2:1, the number of moles of Ca(OH)2 needed to react with 0.3995 mol of NH4Cl is also 0.3995 mol.
Next, let's find the molar mass of Ca(OH)2:
Molar mass of Ca(OH)2 = 40.08g/mol (Ca) + 2(1.01g/mol)(H) + 16.00g/mol (O)
= 74.10g/mol
Finally, let's calculate the mass of calcium hydroxide (Ca(OH)2) needed to react with 0.3995 mol:
Mass of Ca(OH)2 = number of moles × molar mass
= 0.3995 mol × 74.10g/mol
≈ 29.65g
Therefore, the mass of calcium hydroxide that will react with 21.4g of ammonium chloride is approximately 29.65g.
To find the mass of calcium hydroxide that will react with 21.4g of ammonium chloride, we need to determine the stoichiometry of the reaction.
The balanced equation is:
2NH4Cl + Ca(OH)2 → 2NH3 + CaCl2 + 2H2O
From the balanced equation, we can see that 2 moles of ammonium chloride (NH4Cl) react with 1 mole of calcium hydroxide (Ca(OH)2).
1 mole of Ca(OH)2 has a molar mass of 74.093 g/mol.
To find the mass of Ca(OH)2 used, we can use the following formula:
Mass of Ca(OH)2 = (mass of NH4Cl * molar mass of Ca(OH)2) / (molar mass of NH4Cl * stoichiometric coefficient of Ca(OH)2)
Substituting the given values:
mass of NH4Cl = 21.4g
molar mass of Ca(OH)2 = 74.093 g/mol
molar mass of NH4Cl = 53.491 g/mol
stoichiometric coefficient of Ca(OH)2 = 1
Mass of Ca(OH)2 = (21.4g * 74.093 g/mol) / (53.491 g/mol * 1)
Simplifying the equation:
Mass of Ca(OH)2 = 30.048 g
Therefore, the mass of calcium hydroxide that will react with 21.4g of ammonium chloride is approximately 30.048g.
To determine the mass of calcium hydroxide that will react with 21.4g of ammonium chloride, you need to use the stoichiometry of the balanced chemical equation.
First, you need to calculate the molar masses of the compounds involved in the reaction. The molar mass of ammonium chloride (NH4Cl) is calculated as follows:
NH4Cl = (1 x molar mass of N) + (4 x molar mass of H) + (1 x molar mass of Cl)
N: molar mass of nitrogen = 14.01 g/mol
H: molar mass of hydrogen = 1.01 g/mol
Cl: molar mass of chlorine = 35.45 g/mol
Therefore, molar mass of NH4Cl = (1 x 14.01) + (4 x 1.01) + 35.45 = 53.49 g/mol
Next, use the stoichiometry of the balanced equation to determine the molar ratio between NH4Cl and Ca(OH)2. From the equation:
2NH4Cl + Ca(OH)2 → 2NH3 + CaCl2 + 2H2O
The ratio between NH4Cl and Ca(OH)2 is 2:1. This means that you need half as many moles of Ca(OH)2 as there are moles of NH4Cl.
To calculate the number of moles of NH4Cl, divide the given mass of NH4Cl by its molar mass:
moles of NH4Cl = mass / molar mass = 21.4 g / 53.49 g/mol = 0.4 mol
Since the ratio between NH4Cl and Ca(OH)2 is 2:1, the number of moles of Ca(OH)2 needed is half of that:
moles of Ca(OH)2 = 0.4 mol / 2 = 0.2 mol
Finally, to determine the mass of Ca(OH)2, multiply the number of moles by its molar mass:
mass of Ca(OH)2 = moles of Ca(OH)2 x molar mass of Ca(OH)2
The molar mass of Ca(OH)2 is calculated as follows:
Ca(OH)2 = (1 x molar mass of Ca) + (2 x molar mass of O) + (2 x molar mass of H)
Ca: molar mass of calcium = 40.08 g/mol
O: molar mass of oxygen = 16.00 g/mol
H: molar mass of hydrogen = 1.01 g/mol
Therefore, molar mass of Ca(OH)2 = (1 x 40.08) + (2 x 16.00) + (2 x 1.01) = 74.09 g/mol
Substituting the values:
mass of Ca(OH)2 = 0.2 mol x 74.09 g/mol = 14.82 g
Therefore, the mass of calcium hydroxide that will react with 21.4g of ammonium chloride is 14.82g.