The altitude of an airplane is decreasing at a rate of 45 ft per second what is the change in altitude of the airplane over period of over a period of 23 seconds
To calculate the change in altitude of the airplane over a period of 23 seconds, we need to multiply the rate of decrease (45 ft per second) by the time (23 seconds).
Change in altitude = Rate × Time
Change in altitude = 45 ft/s × 23 s
Change in altitude = 1035 ft
Therefore, the change in altitude of the airplane over a period of 23 seconds is 1035 feet.
-26 * 54 / 247
To solve the expression -26 * 54 / 247, we follow the order of operations (PEMDAS/BODMAS).
First, we multiply -26 and 54:
-26 * 54 = -1,404
Next, we divide the result by 247:
-1,404 / 247 = -5.682
Therefore, -26 * 54 / 247 equals approximately -5.682.
-10.7x(-49.9)
To solve the expression -10.7x(-49.9), we simply multiply -10.7 by -49.9.
-10.7 * (-49.9) = 533.93
Therefore, -10.7x(-49.9) equals 533.93.
To find the change in altitude, we can use the formula:
Change in altitude = Rate of decrease × Time
Given:
Rate of decrease = 45 ft per second
Time = 23 seconds
Substituting the values into the formula:
Change in altitude = 45 ft/second × 23 seconds
Calculating the result:
Change in altitude = 1035 ft
Therefore, the change in altitude of the airplane over a period of 23 seconds is 1035 feet.
To find the change in altitude of the airplane over a period of 23 seconds, we need to multiply the rate of change (given as 45 ft per second) by the duration (23 seconds).
The formula we can use is:
Change in altitude = Rate of change × Duration
Substituting the given values:
Change in altitude = 45 ft/s × 23 s
Calculating this:
Change in altitude = 1035 ft
Therefore, the altitude of the airplane will decrease by 1035 feet over a period of 23 seconds.