what is the length of ab with end points a 3 2 and b 8 14
To find the length of segment AB with endpoints A(3, 2) and B(8, 14), we can use the distance formula.
The distance formula is given as:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
So, substituting the coordinates, we have:
d = sqrt((8 - 3)^2 + (14 - 2)^2)
= sqrt(5^2 + 12^2)
= sqrt(25 + 144)
= sqrt(169)
= 13
Therefore, the length of segment AB is 13 units.
To find the length of a line segment with endpoints A(3,2) and B(8,14), you can use the distance formula, which is based on the Pythagorean theorem. The distance formula is:
√((x2-x1)² + (y2-y1)²)
Substituting the given coordinates of A(3,2) and B(8,14) into the formula, we have:
√((8-3)² + (14-2)²)
Simplifying further:
√(5² + 12²)
√(25 + 144)
√169
Therefore, the length of segment AB is equal to 13.
To find the length of segment AB with endpoints A(3, 2) and B(8, 14), we can use the distance formula. The distance formula is derived from the Pythagorean theorem and can be used to find the distance between two points in a coordinate plane.
The formula is:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, (x1, y1) represents the coordinates of point A (3, 2), and (x2, y2) represents the coordinates of point B (8, 14).
Plugging in the values into the formula, we get:
Distance = √((8 - 3)^2 + (14 - 2)^2)
Simplifying:
Distance = √(5^2 + 12^2)
Distance = √(25 + 144)
Distance = √169
Distance = 13
Therefore, the length of segment AB with endpoints A(3, 2) and B(8, 14) is 13 units.