Lake Acid has a depth of 120ft below the surfacel. Lake Placid is ⅓ as deep. How deep is Lake Placid? Use appropriate integer to account for elevation.
Lake Placid is 40ft deep.
Multiply -2 ⅕ by -8. Write as simplifed mixed number
To multiply -2 ⅕ by -8, we can convert the mixed number to an improper fraction.
-2 ⅕ = (-2 * 5 + 1) / 5 = -11/5.
Now, multiply -11/5 by -8:
-11/5 * -8 = (11/5) * (8/1) = 88/5.
To write this as a simplified mixed number, we divide the numerator (88) by the denominator (5) and express the quotient as a mixed number:
88 ÷ 5 = 17 remainder 3.
Therefore, the simplified mixed number is 17 3/5.
A tank holds 500 gallons of water. It drains 24 gallons of water in 6 minutes. What is the change in water in 1 minute? (remember integer representation is necessary)
To find the change in water in 1 minute, we can divide the change in water over 6 minutes by 6.
The change in water in 6 minutes is -24 gallons, as the water is being drained.
Therefore, the change in water in 1 minute is -24/6 = -4 gallons.
Since the water is being drained, the change in water in 1 minute is -4 gallons.
To find the depth of Lake Placid, we'll start by determining how much ⅓ of the depth of Lake Acid is.
Lake Acid has a depth of 120 ft.
To find ⅓ of 120 ft, we divide 120 by 3.
120 ft ÷ 3 = 40 ft
Therefore, Lake Placid is 40 ft deep.
To find the depth of Lake Placid, which is ⅓ as deep as Lake Acid, you need to divide the depth of Lake Acid by 3.
Depth of Lake Acid = 120 ft
Depth of Lake Placid = Depth of Lake Acid / 3
Depth of Lake Placid = 120 ft / 3
Depth of Lake Placid = 40 ft
Therefore, Lake Placid is 40 feet deep.