The mass of an object doubles. What happens to the gravitational force between it and another object whose mass stays the same, assuming they remain the same distance apart?(1 point)
The amount of the gravitational force quadruples.
The amount of the gravitational force quadruples.
The amount of the gravitational force remains the same.
The amount of the gravitational force remains the same.
The amount of the gravitational force decreases by one-half.
The amount of the gravitational force decreases by one-half.
The amount of the gravitational force doubles.
The amount of the gravitational force doubles.
The amount of the gravitational force doubles.
The amount of gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In this case, the mass of one object doubles while the other object's mass remains the same, and the distance between them stays constant.
To determine the effect on the gravitational force, we can use the formula:
F = G * (m1 * m2) / r^2,
where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between them.
In our scenario, if the mass of one object doubles, the new mass (m1') will be equal to 2 times the original mass (m1). The other object's mass (m2) remains the same. Therefore, the new gravitational force (F') can be calculated as:
F' = G * (m1' * m2) / r^2.
Substituting the value of m1' = 2 * m1, we get:
F' = G * (2 * m1 * m2) / r^2.
Simplifying, we find:
F' = 2 * (G * (m1 * m2) / r^2).
This shows that the new gravitational force (F') is twice the original force (F). Therefore, the correct answer is:
The amount of the gravitational force doubles.