The Distributive Property Quick Check
3 of 53 of 5 Items
Question
Sven is making a school supply display. Sven has 52 notebooks and 42 binders. Sven wants to group the supplies in the display so that there are an equal number of supplies in each group. If we know that Sven puts the same number of notebooks and the same number of binders into each group, how many groups did he display and how many of each item went into each group? Represent your answer using the Distributive Property of Multiplication over Addition.(1 point)
Responses
Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52+42).
Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 plus 42 right parenthesis .
Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52×42).
Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 times 42 right parenthesis .
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26×21).
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 times 21 right parenthesis .
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21).
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 plus 21 right parenthesis .
Skip to navigation
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21).
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 plus 21 right parenthesis .
Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21).
To determine the answer to the question, you need to understand the Distributive Property of Multiplication over Addition. According to the Distributive Property, when you have a number multiplied by the sum of two or more numbers, you can distribute the multiplication to each term inside the parentheses.
In this case, Sven wants to group the supplies so that there are an equal number of supplies in each group. To do this, he needs to put the same number of notebooks and binders into each group.
Given that Sven has 52 notebooks and 42 binders, he needs to determine how many groups he can make and how many of each item will go into each group.
Since Sven wants an equal number of supplies in each group, he needs to find the greatest common divisor (GCD) of 52 and 42. In this case, the GCD is 2.
Once you find the GCD, you can divide the total number of notebooks and binders by the GCD to determine how many of each item goes into each group.
In this case, the total number of notebooks is 52 and the GCD is 2, so each group will have 52/2 = 26 notebooks.
Similarly, the total number of binders is 42 and the GCD is 2, so each group will have 42/2 = 21 binders.
Therefore, Sven made 2 groups, with 26 notebooks and 21 binders in each group.
Using the Distributive Property, the answer can be shown as 2(26+21) or 2(26×21). Both expressions represent the same result.