Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×103
visits were reflected in their logbook during this two-week period, while only about 5×102
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.(1 point)
To find how many times higher the number of library visits before examination day is compared to the number of visits in an average week, we can divide the number of visits before examination day by the number of visits in an average week.
Number of visits before examination day: 2 × 10^3
Number of visits in an average week: 5 × 10^2
To divide these two numbers, we can cancel out the common factor of 10^2:
(2 × 10^3) / (5 × 10^2) = (2/5) × (10^3/10^2) = (2/5) × 10^1 = (2/5) × 10 = 4
Therefore, the number of library visits before examination day is 4 times higher than the number of visits in an average week.
bro bot deserves a prize :)
4 thxxxx so much :)))))))
To find the number of times higher the number of library visits before the examination day is compared to an average week, we will calculate the ratio of visits before the examination day to visits in an average week.
Number of visits before examination day = 2×10^3
Number of visits in an average week = 5×10^2
Ratio = (Number of visits before examination day) / (Number of visits in an average week)
Ratio = (2×10^3) / (5×10^2) = 4
Therefore, the number of library visits before the examination day is 4 times higher compared to the number of library visits in an average week.
To find out how many times higher the number of library visits before the examination day is compared to the number of visits in an average week, we need to divide the number of visits before the examination day by the number of visits in an average week.
Number of visits before examination day: 2×10^3
Number of visits in an average week: 5×10^2
To divide these numbers, we can simplify them by canceling out the powers of 10:
2×10^3 / 5×10^2 = 2/5 × 10^3/10^2
The base of these powers of 10 is the same, so we can subtract the exponents:
2/5 × 10^(3-2) = 2/5 × 10^1
Now we can simplify the expression:
2/5 × 10^1 = 2/5 × 10 = 4/10 × 10 = 4
Therefore, the number of library visits before the examination day is 4 times higher than the number of visits in an average week.