2 grams of potassium (K) reacts with 5 grams of (O). According to the law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
To determine the mass of potassium oxide (K2O) produced, we first need to calculate the molar masses of potassium (K) and oxygen (O).
The molar mass of K is 39.10 g/mol, and the molar mass of O is 16.00 g/mol.
Since we're given the mass of K and O in grams, we can convert these masses to moles by dividing each mass by its respective molar mass:
moles of K = 2 g / (39.10 g/mol) = 0.051 mol
moles of O = 5 g / (16.00 g/mol) = 0.312 mol
From the balanced chemical equation of the reaction between K and O:
2K + O2 -> 2K2O
We can see that for every 2 moles of K, the reaction produces 2 moles of K2O.
Since we have 0.051 mol of K, we'll have the same number of moles of K2O produced:
moles of K2O = 0.051 mol
Finally, we can convert the moles of K2O to grams by multiplying by its molar mass:
mass of K2O = 0.051 mol * (94.20 g/mol) = 4.812 g
Therefore, according to the law of Conservation of Mass, 2 grams of potassium (K) reacts with 5 grams of oxygen (O) to produce 4.812 grams of potassium oxide (K2O).
2 grams of potassium (K) reacts with 5 grams of (O). According to the law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
A. 5 grams
B. 2 grams
C. 7 grams
D. 10 grams
To determine the mass of potassium oxide (K2O) produced, we need to calculate the molar masses of potassium (K) and oxygen (O).
The molar mass of K is 39.10 g/mol, and the molar mass of O is 16.00 g/mol.
Since we're given the mass of K and O in grams, we can convert these masses to moles by dividing each mass by its respective molar mass:
moles of K = 2 g / (39.10 g/mol) = 0.051 mol
moles of O = 5 g / (16.00 g/mol) = 0.312 mol
From the balanced chemical equation of the reaction between K and O:
2K + O2 -> 2K2O
We can see that for every 2 moles of K, the reaction produces 2 moles of K2O.
Since we have 0.051 mol of K, we'll have the same number of moles of K2O produced:
moles of K2O = 0.051 mol
Finally, we can convert the moles of K2O to grams by multiplying by its molar mass:
mass of K2O = 0.051 mol * (94.20 g/mol) = 4.812 g
Therefore, according to the law of Conservation of Mass, 2 grams of potassium (K) reacts with 5 grams of oxygen (O) to produce 4.812 grams of potassium oxide (K2O). Thus, none of the given options (A, B, C, or D) is the correct answer.
2 grams of potassium (K) reacts with 5 grams of (O). According to the law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced?
A. 5 grams
B. 2 grams
C. 7 grams
D. 10 grams
Since potassium (K) has a molar mass of 39.10 g/mol and oxygen (O) has a molar mass of 16.00 g/mol, we can begin by converting the masses of potassium (K) and oxygen (O) to moles:
moles of K = 2 g / (39.10 g/mol) ≈ 0.051 mol
moles of O = 5 g / (16.00 g/mol) ≈ 0.312 mol
According to the balanced chemical equation for the reaction between K and O:
2K + O2 -> 2K2O
We can see that for every 2 moles of K, the reaction produces 2 moles of K2O.
Since we have 0.051 mol of K, we'll have the same number of moles of K2O produced:
moles of K2O = 0.051 mol * 2 = 0.102 mol
Finally, we can convert the moles of K2O to grams by multiplying by its molar mass:
mass of K2O = 0.102 mol * (94.20 g/mol) ≈ 9.620 g
Therefore, according to the law of Conservation of Mass, 2 grams of potassium (K) reacts with 5 grams of oxygen (O) to produce approximately 9.620 grams of potassium oxide (K2O). Thus, the correct answer is not among the given options, A, B, C, or D.
To find the mass of potassium oxide (K2O) produced, we first need to calculate the molar masses of potassium (K) and oxygen (O).
The molar mass of potassium (K) is 39.10 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol.
Next, we need to determine the number of moles of K and O in the given amounts.
For potassium (K):
Number of moles = mass / molar mass
Number of moles of K = 2 g / 39.10 g/mol = 0.0511 mol
For oxygen (O):
Number of moles = mass / molar mass
Number of moles of O = 5 g / 16.00 g/mol = 0.3125 mol
According to the balanced chemical equation for the reaction between K and O, we know that the ratio of K to O in K2O is 2:1.
Since potassium (K) is the limiting reactant, the amount of K2O produced will be determined by the number of moles of K. So, the number of moles of K2O produced will be half the number of moles of K.
Number of moles of K2O = 0.0511 mol / 2 = 0.0255 mol
Finally, we can calculate the mass of K2O produced using the molar mass of K2O, which is 94.20 g/mol.
Mass of K2O = number of moles × molar mass
Mass of K2O = 0.0255 mol × 94.20 g/mol = 2.40 g
Therefore, 2 grams of potassium (K) reacting with 5 grams of oxygen (O) will produce 2.40 grams of potassium oxide (K2O) according to the law of Conservation of Mass.
To determine the number of grams of potassium oxide (K2O) produced, we need to use the law of Conservation of Mass. According to this law, matter cannot be created or destroyed during a chemical reaction, only rearranged.
First, let's write down the balanced chemical equation for the reaction between potassium and oxygen:
4K + O2 -> 2K2O
From the balanced equation, we can see that 4 moles of potassium (K) react with 1 mole of oxygen (O2) to produce 2 moles of potassium oxide (K2O).
Next, we need to convert the given masses of potassium (K) and oxygen (O) into moles. To do this, we use the molar mass of each element:
Molar mass of potassium (K) = 39.1 g/mol
Molar mass of oxygen (O) = 16.0 g/mol
Number of moles of potassium (K) = 2 g / 39.1 g/mol ≈ 0.051 mol
Number of moles of oxygen (O) = 5 g / 16.0 g/mol ≈ 0.312 mol
Since the stoichiometry of the reaction is 4:1 for potassium and oxygen, we compare the moles of the reacting elements.
From the balanced equation, we can see that 4 moles of potassium (K) react with 1 mole of oxygen (O2) to produce 2 moles of potassium oxide (K2O).
Therefore, 0.051 mol of potassium will react with 0.051 mol / 4 mol ≈ 0.0128 mol of oxygen.
To calculate the grams of potassium oxide formed, we multiply the moles of oxygen (O) by the molar mass of potassium oxide (K2O):
Molar mass of potassium oxide (K2O) = (39.1 g/mol x 2) + (16.0 g/mol x 1) = 78.2 g/mol
Number of grams of potassium oxide (K2O) = 0.0128 mol x 78.2 g/mol ≈ 1 g
Therefore, 2 grams of potassium (K) reacts with 5 grams of oxygen (O) to produce approximately 1 gram of potassium oxide (K2O) according to the law of Conservation of Mass.