2Hg + O2---> 2HgO If the total mass of the product, mercuric oxide, HgO, is 433.2 grams, what is the total mass of the Mercury and Oxygen on the reactants side of the equation? Type your answer in the below box.
The total mass of the reactants can be determined by using the Law of Conservation of Mass. According to this law, the total mass of the reactants must be equal to the total mass of the products.
In this balanced chemical equation, the coefficient of Hg (mercury) is 2, and the coefficient of O2 (oxygen) is 1.
To calculate the mass of mercury, we multiply the coefficient of Hg (2) by its atomic mass (around 200.59 g/mol).
Mass of mercury = 2 * 200.59 g/mol = 401.18 g
To calculate the mass of oxygen, we multiply the coefficient of O2 (1) by its atomic mass (around 32.00 g/mol).
Mass of oxygen = 1 * 32.00 g/mol = 32.00 g
Therefore, the total mass of mercury and oxygen on the reactants side of the equation is:
Total mass = mass of mercury + mass of oxygen
Total mass = 401.18 g + 32.00 g
Total mass = 433.18 g
So, the total mass of mercury and oxygen on the reactants side of the equation is approximately 433.18 grams.
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I apologize for the mistake. Let's calculate it correctly.
In the balanced chemical equation 2Hg + O2 -> 2HgO, we have 2 moles of Hg reacting with 1 mole of O2 to form 2 moles of HgO.
To find the total mass of mercury and oxygen on the reactants' side, we need to determine the molar masses of Hg and O2.
The molar mass of Hg is approximately 200.59 g/mol.
The molar mass of O2 is approximately 32.00 g/mol. Note that O2 exists as a diatomic molecule in this reaction.
Given that we have 2 moles of Hg, the mass of Hg is calculated as follows:
Mass of Hg = 2 moles Hg * 200.59 g/mol
Mass of Hg = 401.18 g
Given that we have 1 mole of O2, the mass of O2 is calculated as follows:
Mass of O2 = 1 mole O2 * 32.00 g/mol
Mass of O2 = 32.00 g
The total mass of mercury and oxygen on the reactants' side is:
Total mass = Mass of Hg + Mass of O2
Total mass = 401.18 g + 32.00 g
Total mass = 433.18 g
So, the total mass of mercury and oxygen on the reactants' side of the equation is approximately 433.18 grams.
To find the total mass of Mercury (Hg) and Oxygen (O) on the reactants side of the equation, we need to examine the stoichiometry of the balanced chemical equation. The coefficient in front of each element represents the molar ratio and can be used to determine the masses.
From the balanced equation: 2Hg + O2 -> 2HgO
We can see that for every 2 moles of Hg, 2 moles of HgO are produced. This means that the molar mass of Hg is equal to the molar mass of HgO.
The molar mass of HgO can be calculated by adding the atomic masses of Hg and O:
HgO = 200.59 g/mol (Hg) + 16.00 g/mol (O) = 216.59 g/mol
Now, we can set up a proportion to find the mass of Hg and O:
(2 moles of Hg)/(2 moles of HgO) = (x grams of Hg)/(433.2 grams of HgO)
Simplifying the proportion:
(1 mole of Hg)/(1 mole of HgO) = (x grams of Hg)/(216.59 grams of HgO)
Cross multiplying:
1 * 216.59 = x * 1
x = 216.59 grams
Therefore, the total mass of Mercury (Hg) and Oxygen (O) on the reactants side of the equation is 216.59 grams.
To find the total mass of mercury (Hg) and oxygen (O2) on the reactants side of the equation, we need to calculate the molar masses and use stoichiometry.
First, let's calculate the molar mass of mercury (Hg) and oxygen (O2):
- Mercury (Hg) has a molar mass of 200.59 g/mol.
- Oxygen (O2) has a molar mass of 32.00 g/mol.
Next, we can set up a proportion using the molar ratios from the balanced chemical equation:
2Hg + O2 -> 2HgO
From the equation, we can see that:
- 2 moles of mercury react with 1 mole of oxygen to produce 2 moles of mercuric oxide.
Using these ratios, we can calculate the moles of mercury and oxygen:
- Moles of mercury (Hg) = (mass of Hg / molar mass of Hg)
- Moles of oxygen (O2) = (mass of O2 / molar mass of O2)
Assuming the mass of mercuric oxide (HgO) is 433.2 grams, we can now calculate the moles of mercury (Hg) and oxygen (O2).
1) Moles of mercury (Hg):
- Moles of Hg = (mass of HgO * 2) / molar mass of HgO
- Moles of Hg = (433.2 * 2) / (200.59 + 16.00)
2) Moles of oxygen (O2):
- Moles of O2 = (mass of HgO * 1) / molar mass of HgO
- Moles of O2 = (433.2 * 1) / (200.59 + 16.00)
Now, we can calculate the total mass of mercury and oxygen on the reactants side:
1) Total mass of mercury (Hg):
- Mass of Hg = (moles of Hg * molar mass of Hg)
2) Total mass of oxygen (O2):
- Mass of O2 = (moles of O2 * molar mass of O2)
Calculating the values should give you the total mass of mercury and oxygen on the reactants side of the equation.