The other tooth of an airplane is decreasing at a rate of 45 ft./s. What is the change in altitude of the airplane over a period of 28 seconds
A. 73 feet
B. -1260 feet
C. 1260 feet
D. -73 feet
To solve this problem, we need to find the change in altitude of the airplane over a period of 28 seconds.
We are given that the other tooth (presumably engine) of the airplane is decreasing at a rate of 45 ft/s. This means that the altitude of the airplane is decreasing at a rate of 45 ft/s.
The change in altitude is calculated by multiplying the rate of change (45 ft/s) by the time (28 seconds):
Change in altitude = rate of change x time
Change in altitude = 45 ft/s x 28 s
Change in altitude = 1260 feet
Therefore, the change in altitude of the airplane over a period of 28 seconds is 1260 feet.
The answer is C. 1260 feet.
To find the change in altitude of the airplane over a period of 28 seconds, we need to multiply the rate of decrease by the time period.
Given that the rate of decrease is 45 ft./s and the time period is 28 seconds, we have:
Change in altitude = Rate of decrease × Time period
Change in altitude = 45 ft./s × 28 s
Change in altitude = 1260 ft
Therefore, the change in altitude of the airplane over a period of 28 seconds is 1260 feet.
So, the answer is: C. 1260 feet.
To find the change in altitude of the airplane over a period of 28 seconds, we need to multiply the rate of decrease of the tooth by the time interval.
Given:
Rate of decrease of the tooth = 45 ft./s
Time interval = 28 seconds
First, we calculate the change in altitude using the formula:
Change in altitude = Rate of decrease of the tooth × Time interval
Change in altitude = 45 ft./s × 28 seconds
Now we can calculate the change in altitude:
Change in altitude = 1260 feet
Therefore, the change in altitude of the airplane over a period of 28 seconds is 1260 feet (option C).