Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2\times10^3
visits were reflected in their logbook during this two-week period, while only about 5\times10^2
were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.(1 point)
To find out how many times higher the number of library visits before the examination day is compared to the average week, we need to divide the number of visits before the examination day by the number of visits in an average week:
(2*10^3) / (5*10^2) = 2*10^3 / (5*10^2) = 2/5 * 10^(3-2) = 2/5 * 10^1 = 2/5 * 10 = 4
Therefore, the number of library visits before the examination day is 4 times higher than the number of visits in an average week.
To find how many times higher the number of library visits before the examination day is compared to an average week, we need to divide the number of visits before the examination day by the number of visits in an average week.
The number of visits before the examination day is 2 × 10^3.
The number of visits in an average week is 5 × 10^2.
To divide these two numbers, we can write them in scientific notation form:
2 × 10^3 ÷ 5 × 10^2
Since the bases (2 and 5) are the same, we can divide the coefficients:
(2 ÷ 5) × 10^3 ÷ 10^2
2 ÷ 5 = 0.4
Now, to divide the powers of 10, we subtract the exponent in the denominator (10^2) from the exponent in the numerator (10^3):
10^3 ÷ 10^2 = 10^(3-2) = 10^1 = 10
Therefore, the number of library visits before the examination day is 0.4 × 10 = 4 times higher compared to the number of visits in an average week.
To find out how many times higher the number of library visits before the examination day is compared to an average week, we need to calculate the ratio between the two.
The number of visits in the two-week period is approximately 2 * 10^3, while the number of visits in an average week is about 5 * 10^2.
To calculate the ratio, we divide the number of visits in the two-week period by the number of visits in an average week:
(2 * 10^3) / (5 * 10^2) = (2/5) * (10^3 / 10^2) = (2/5) * 10^(3-2) = (2/5) * 10^1 = 2 * 10/5 = 4/5 = 0.8
This means that the number of library visits before the examination day is 0.8 times higher than the number of visits in an average week.
However, since the question asks for a whole number answer, we need to round the decimal number. In this case, 0.8 rounds down to 0.
Therefore, the number of library visits before the examination day is 0 times higher than the number of visits in an average week.