On Greg's last visit to his doctor, he complained of feeling tired. Sandra, the registered nurse, withdrew 6.5 mL of blood, which was sent to the lab and tested for iron. The normal range for serum iron in men is 80 to 160mcg / dL. Greg 's iron test showed a blood serum iron level of 39mcg / dL which indicates that Greg has iron-deficiency anemia.

Question

On Greg's last visit to his doctor, he complained of feeling tired. Sandra, the registered nurse, withdrew 6.5 mL of blood, which was sent to the lab and tested for iron. The normal range for serum iron in men is 80 to 160mcg / dL. Greg 's iron test showed a blood serum iron level of 39mcg / dL which indicates that Greg has iron-deficiency anemia.

39 mcg of blood= 1 dL of iron
How many micrograms of iron were in the 6.5-mL sample of Greg's blood? Express your answer using two significant figures.

Answer 1

To find the micrograms of iron in the 6.5-mL sample of Greg's blood, we can use the conversion factor provided: 39 mcg of blood = 1 dL of iron.

First, we need to convert the volume of blood, 6.5 mL, to deciliters (dL). Since there are 10 milliliters in 1 deciliter, we divide 6.5 mL by 10:

6.5 mL / 10 = 0.65 dL

Now, we can use the conversion factor to find the micrograms of iron:

0.65 dL * 39 mcg/dL = 25.35 mcg of iron

Rounding to two significant figures, the 6.5-mL sample of Greg's blood contains approximately 25 mcg of iron.

Answer 2

To find the amount of iron in the 6.5 mL sample of Greg's blood, we can use the given information that 39 mcg of iron corresponds to 1 dL of blood.

First, let's convert 6.5 mL to dL:
1 dL = 100 mL
6.5 mL = 6.5/100 dL = 0.065 dL

Now, we can calculate the amount of iron in the 6.5 mL sample:
Amount of iron = (39 mcg/dL) * (0.065 dL) = 2.535 mcg

Therefore, there were approximately 2.54 micrograms of iron in the 6.5-mL sample of Greg's blood.

Answer 3

To find the amount of micrograms of iron in the 6.5 mL sample of Greg's blood, we can use the given conversion ratio:

39 mcg of iron = 1 dL of blood.

Now, we know the volume of the blood sample is 6.5 mL. We need to convert this to deciliters (dL) before we can use the conversion ratio:

6.5 mL * (1 dL / 100 mL) = 0.065 dL.

Now we can use the conversion ratio to find the amount of micrograms of iron:

0.065 dL * 39 mcg of iron / 1 dL = 2.535 mcg of iron.

Rounding to two significant figures, we get that there are approximately 2.5 micrograms of iron in the 6.5 mL sample of Greg's blood.