Match each compound name and formula. Be sure to use your periodic table and polyatomic ion chart.

Question 3 options:

Beryllium hydroxide

Iron III permanganate

Barium bromide

1.
BaBr2

2.
Fe(MnO4)3

3.
Be(OH)2

1. BaBr2 - Barium bromide

2. Fe(MnO4)3 - Iron III permanganate
3. Be(OH)2 - Beryllium hydroxide

(C.7D)

Data Table: sample A = low boiling pt, not electrical conductor, not soluble in water; Sample B = high boiling pt, conducts electricity, dissolves in water

Carl and Sally designed an experiment to compare and contrast the properties of compounds. After designing their experiment, Carl and Sally tabulated the data in the table seen here. Based on their data, compound B most likely represents

Question 4 options:

A covalent compound

An ionic compound

A metallic compound

Based on the data provided, compound B most likely represents an ionic compound. Ionic compounds often have high boiling points, conduct electricity when dissolved in water (in the form of ions), and are soluble in water.

Listed in the Item Bank are some important labels for sections of the image below. Match each label to the corresponding area it identifies in the image.

Venn Diagram comparing metals, nonmetals, metalloids

Question 1 options:

May have no luster

Can be electrical conductors

Hydrogen, Oxygen and Chlorine

Comprised of atoms

Can exchange electrons with each other to form ionic compounds

Tin, Calcium and Potassium

Silicon, Arsenic and Antimony

1. May have no luster - Nonmetals

2. Can be electrical conductors - Metals
3. Hydrogen, Oxygen and Chlorine - Nonmetals
4. Comprised of atoms - All sections (Metals, Nonmetals, Metalloids)
5. Can exchange electrons with each other to form ionic compounds - Metals and Nonmetals
6. Tin, Calcium and Potassium - Metals
7. Silicon, Arsenic and Antimony - Metalloids

To match each compound name and formula, we can use the information from the periodic table and polyatomic ion chart.

1. Beryllium hydroxide: The symbol for beryllium is Be, and the hydroxide ion is OH-. The hydroxide ion has a charge of -1. Since beryllium has a charge of +2, we need two hydroxide ions to balance the charge. Therefore, the formula for beryllium hydroxide is Be(OH)2.

2. Iron III permanganate: The symbol for iron is Fe, and the permanganate ion is MnO4-. The permanganate ion has a charge of -1. Since iron III has a charge of +3, we need three permanganate ions to balance the charge. Therefore, the formula for iron III permanganate is Fe(MnO4)3.

3. Barium bromide: The symbol for barium is Ba, and the bromide ion is Br-. The bromide ion has a charge of -1. Since barium has a charge of +2, we need two bromide ions to balance the charge. Therefore, the formula for barium bromide is BaBr2.

To match each compound name with the correct formula, we'll need to use the periodic table and the polyatomic ion chart.

1. Beryllium hydroxide:
To find the formula for this compound, we first need to determine the charge of the beryllium ion (Be). By referring to the periodic table, we can see that beryllium is in group 2, which means it typically forms a 2+ cation, Be^2+.
Next, we need to determine the charge of the hydroxide ion (OH-). From the polyatomic ion chart, we can see that hydroxide is a polyatomic ion with a charge of -1.

Since the total charge of a compound must be neutral, we need two hydroxide ions to balance the 2+ charge of beryllium. Therefore, the formula for beryllium hydroxide is Be(OH)2.

2. Iron III permanganate:
To determine the formula for this compound, we first need to determine the charge of the iron ion (Fe). By referring to the periodic table, we can see that iron is in group 8, which means it typically forms either a 2+ or 3+ cation.

In this case, the compound is referred to as "Iron III permanganate," indicating that the iron ion has a charge of 3+. The permanganate ion (MnO4-) has a charge of -1. To balance the charges, we need three permanganate ions to react with one iron (III) ion. Therefore, the formula for this compound is Fe(MnO4)3.

3. Barium bromide:
To determine the formula for this compound, we first need to determine the charge of the barium ion (Ba). By referring to the periodic table, we can see that barium is in group 2, which means it typically forms a 2+ cation, Ba^2+.

Similarly, the bromide ion (Br-) has a charge of -1. To balance the charges, we need two bromide ions to react with one barium ion. Therefore, the formula for barium bromide is BaBr2.

So, matching the compound names with their formulas:

1. Beryllium hydroxide: Be(OH)2
2. Iron III permanganate: Fe(MnO4)3
3. Barium bromide: BaBr2