Enter the elements in leritine
C22 H29 CIN2 O2
The elements in the compound are:
Carbon (C)
Hydrogen (H)
Chlorine (Cl)
Nitrogen (N)
Oxygen (O)
To determine the elements in the compound C22H29ClN2O2, you can break down the chemical formula and identify each element:
C22 - This indicates there are 22 carbon (C) atoms.
H29 - This indicates there are 29 hydrogen (H) atoms.
Cl - This indicates there is 1 chlorine (Cl) atom.
N2 - This indicates there are 2 nitrogen (N) atoms.
O2 - This indicates there are 2 oxygen (O) atoms.
Therefore, the elements present in the compound are carbon (C), hydrogen (H), chlorine (Cl), nitrogen (N), and oxygen (O).
To determine the elements present in the compound C22H29ClN2O2, we can break down the chemical formula and analyze each individual element.
1. C22: This indicates the presence of 22 carbon (C) atoms.
2. H29: This indicates the presence of 29 hydrogen (H) atoms.
3. Cl: This represents one chlorine (Cl) atom.
4. N2: This indicates the presence of two nitrogen (N) atoms.
5. O2: This represents two oxygen (O) atoms.
So, the elements present in the compound are carbon (C), hydrogen (H), chlorine (Cl), nitrogen (N), and oxygen (O).