An amusement park sells child and adult tickets at a ratio of 8:1. On Saturday, they should 147 more child tickets than adult tickets. How many tickets did the amusement park sell on Saturday?
Let X be the number of adult tickets sold on Saturday
Therefore, the number of child tickets sold is 8X
They sold 147 more child tickets than adult tickets, so 8X=X+147
7X=147
X=<<21=21>>21
The number of tickets sold on Saturday was 21+147=<<21+147=168>>168. Answer: \boxed{168}.
An amusement park sells child and adult tickets at a ratio of 8:1. On Saturday, they should 147 more child tickets than adult tickets. How many tickets did the amusement park sell on Saturday?
(Step by step)
Let's assume that the number of adult tickets sold on Saturday is x.
According to the given ratio, the number of child tickets sold will be 8x.
We are told that on Saturday, there were 147 more child tickets sold than adult tickets, so we can set up the following equation:
8x = x + 147
To solve this equation, we can subtract x from both sides:
7x = 147
Now, divide both sides of the equation by 7:
x = 147 / 7
Simplifying the right side, we get:
x = 21
So, the number of adult tickets sold on Saturday is 21.
To find the total number of tickets sold, we need to add the number of adult tickets and child tickets:
21 + 8(21) = 21 + 168 = 189
Therefore, the amusement park sold 189 tickets on Saturday.
An amusement park sells child and adult tickets at a ratio of 8:1. On Saturday, they should 147 more child tickets than adult tickets. How many tickets did the amusement park sell on Saturday? (Only show the proportion)
Let C be the number of child tickets and A be the number of adult tickets sold on Saturday.
The ratio of child tickets to adult tickets is 8:1, so we can write the proportion C/A = 8/1.
According to the problem, there were 147 more child tickets sold than adult tickets, so we can set up another proportion: C = A + 147.
Combining these two proportions, we get the following system of equations:
C/A = 8/1
C = A + 147
To solve this system, we can substitute the value of C from the second equation into the first equation:
(A + 147)/A = 8/1
Now we can cross-multiply and solve for A:
1 * (A + 147) = 8 * A
A + 147 = 8A
147 = 7A
A = 21
So, the number of adult tickets sold on Saturday is 21.
To find the total number of tickets sold, we can substitute this value of A back into the second equation:
C = A + 147
C = 21 + 147
C = 168
Thus, the amusement park sold a total of 21 adult tickets and 168 child tickets on Saturday, for a total of 21 + 168 = 189 tickets.
An amusement park sells child and adult tickets at a ratio of 8:1. On Saturday, they should 147 more child tickets than adult tickets. How many tickets did the amusement park sell on Saturday? (Only show the proportion)
Let x be the number of adult tickets sold on Saturday.
Therefore, the number of child tickets sold is 8x.
According to the problem, there are 147 more child tickets sold than adult tickets, so we can set up the equation 8x = x + 147.
Simplifying this equation, we get 7x = 147.
Dividing both sides of the equation by 7, we find that x = 21.
Thus, the amusement park sold 21 adult tickets and 8x = 8(21) = 168 child tickets on Saturday.
The total number of tickets sold is 21 + 168 = 189. Therefore, the amusement park sold 189 tickets on Saturday.