Find any y-intercepts.
f(x)=4x2−x+8
To find the y-intercept of a function, we substitute 0 for x and solve for y.
f(x) = 4x^2 -x + 8
Setting x to 0, we have:
f(0) = 4(0)^2 - 0 + 8
f(0) = 0 + 0 + 8
f(0) = 8
Therefore, the y-intercept is (0, 8).
To find the y-intercept of a function, we need to set x=0 and solve for y.
Given: f(x) = 4x^2 - x + 8
Setting x = 0, we have:
f(0) = 4(0)^2 - 0 + 8
f(0) = 0 - 0 + 8
f(0) = 8
Therefore, the y-intercept is (0, 8).
To find the y-intercept of the function f(x) = 4x^2 - x + 8, we need to replace x with 0 and solve for y.
So, let's substitute x = 0 into the equation:
f(0) = 4(0)^2 - (0) + 8
= 0 - 0 + 8
= 8
Therefore, the y-intercept of the function f(x) = 4x^2 - x + 8 is (0, 8).