The element phosphorous (P) has an atomic number of 15 and an atomic mass of 31. How many neutrons are in an atom of phosphorous (P)?

To find the number of neutrons in an atom, subtract the atomic number from the atomic mass.

Number of neutrons = Atomic mass - Atomic number
Number of neutrons = 31 - 15
Number of neutrons = 16

Therefore, there are 16 neutrons in an atom of phosphorous (P).

Fluorine has an atomic number of 9 and an atomic mass of 19. How many protons, neutrons, and

The atomic number of an element corresponds to the number of protons in its nucleus. Therefore, fluorine (F) has 9 protons.

To find the number of neutrons, subtract the atomic number from the atomic mass.

Number of neutrons = Atomic mass - Atomic number
Number of neutrons = 19 - 9
Number of neutrons = 10

Therefore, fluorine has 9 protons, 10 neutrons, and 9 electrons (since atoms are neutral and have an equal number of protons and electrons).

To find the number of neutrons in an atom of phosphorous (P), we can subtract the atomic number from the atomic mass.

Atomic mass = number of protons + number of neutrons

Atomic number = number of protons

So, to find the number of neutrons:

Number of neutrons = Atomic mass - Atomic number

Number of neutrons = 31 - 15

Number of neutrons = 16

Therefore, there are 16 neutrons in an atom of phosphorus (P).

To determine the number of neutrons in an atom of phosphorus (P), you can subtract the atomic number from the atomic mass. The atomic number represents the number of protons in the nucleus of an atom, while the atomic mass represents the sum of protons and neutrons present in the nucleus.

In this case, the atomic number of phosphorus is 15, which means it has 15 protons. The atomic mass of phosphorus is 31, which represents the combined mass of protons and neutrons.

Therefore, to find the number of neutrons, subtract the atomic number (15) from the atomic mass (31):

Number of neutrons = Atomic mass - Atomic number = 31 - 15 = 16

So, there are 16 neutrons in an atom of phosphorus (P).