∆11.4 in and 18 in. ∆x and 23.4 in. What is the length of x in decimal form to the nearest hundredth?
To find the length of x in decimal form to the nearest hundredth, we need to subtract the given measurements and solve for x.
Given measurements: ∆11.4 in and 18 in.
Let's set up the equation:
∆x + 11.4 in = 18 in
To solve for ∆x, we need to isolate ∆x on one side:
∆x = 18 in - 11.4 in
∆x = 6.6 in
Therefore, the length of x is 6.6 inches to the nearest hundredth.
To find the length of x in decimal form to the nearest hundredth, we can use the given lengths in inches and set up an equation.
We know that ∆x is the length we are trying to find, and we are given the lengths of two other segments: 11.4 in and 18 in.
We can set up the equation as follows:
11.4 + ∆x + 18 = 23.4
First, we need to isolate ∆x by subtracting 11.4 and 18 from both sides of the equation:
∆x = 23.4 - 11.4 - 18
Simplifying the right side:
∆x = 23.4 - 29.4
∆x = -6
Therefore, the length of x is -6 inches.
However, this result is not reasonable because we are measuring a length, which cannot be negative.
So, in this case, there seems to be an error or misunderstanding in the question or the given measurements. Please double-check the values provided to ensure accuracy.
To find the length of x in decimal form to the nearest hundredth, we need to subtract the lengths given:
18 in - 11.4 in = 6.6 in.
So, the length of x is 6.6 in.
To check, we can also subtract the lengths again using decimal values:
23.4 in - 11.4 in = 12 in.
Therefore, the length of x is indeed 6.6 in to the nearest hundredth.