The height of an equilateral triangle equals 3√2 times the side length. Using 74 for the square root of 3, what is the approximate height in meters of an equilateral triangle with a side length of 8 meters?(
The height of an equilateral triangle is given by the formula h = √3/2 * s, where h is the height and s is the side length.
Given that the height is equal to 3√2 times the side length, we can set up the equation as follows:
3√2 * s = √3/2 * s
Dividing both sides by s gives us:
3√2 = √3/2
Squaring both sides of the equation yields:
18 = 3/4
Now, multiplying both sides by 4 gives us:
72 = 3
Since 72 is not equal to 3, our equation is incorrect.
To find the approximate height in meters of an equilateral triangle with a side length of 8 meters using 74 for the square root of 3, we can use the formula:
h = 74/2 * 8 = 37 * 8 = 296 meters.
To find the height of an equilateral triangle, we can use the formula: height = side length × 3√2.
Given that the side length is 8 meters and 74 is the square root of 3, we can substitute these values into the formula:
height = 8 × (3√2)
= 8 × (3 × 74)
= 8 × 222
= 1776
Therefore, the approximate height of the equilateral triangle is 1776 meters.
To find the height of an equilateral triangle, you can use the formula: height = side length * (√3 / 2).
Given that the side length is 8 meters, we can substitute it into the formula:
height = 8 * (√3 / 2).
Now, you mentioned that we should use 74 as the approximation for √3. So, let's substitute it into the formula:
height = 8 * (74 / 2).
Simplifying, we have:
height = 8 * 37.
Calculating further:
height = 296 meters.
Therefore, the approximate height of the equilateral triangle with a side length of 8 meters is 296 meters.