Use point-slope form to write the equation of a line that passes through the point left bracket, minus, 16, comma, minus, 14, right bracket

(

16
,

14
)
(−16,−14) with slope minus, start fraction, 7, divided by, 8, end fraction

7
8

8
7

.

The equation of a line in point-slope form is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Given that the point is (-16, -14) and the slope is -7/8, the equation of the line is:

y - (-14) = -7/8(x - (-16))

Simplifying,

y + 14 = -7/8(x + 16)

Multiplying through by 8 to eliminate the fraction,

8y + 112 = -7(x + 16)

Expanding,

8y + 112 = -7x - 112

Rearranging terms,

7x + 8y = -224

So, the equation of the line in point-slope form is 7x + 8y = -224.

The point-slope form of a linear equation is given by:

y - y1 = m(x - x1)

Where (x1, y1) is the given point on the line and m is the slope.

Substituting the given values, we have:

y - (-14) = (-7/8)(x -(-16))

Simplifying:

y + 14 = (-7/8)(x + 16)

Now, we can rewrite the equation in a more standard form:

8(y + 14) = -7(x + 16)

Expanding:

8y + 112 = -7x - 112

Rearranging the equation:

7x + 8y = -224

So, the equation of the line in point-slope form is y + 14 = (-7/8)(x + 16) and in standard form is 7x + 8y = -224.

To write the equation of a line using the point-slope form, you need two pieces of information: the coordinates of a point on the line and the slope of the line.

Given that the point is (−16,−14) and the slope is −7/8, you can now use the point-slope form to write the equation of the line.

The point-slope form of a linear equation is:

y - y1 = m(x - x1)

where (x1, y1) are the coordinates of a point on the line and m is the slope.

So, substituting the values into the equation:

y - (-14) = (-7/8)(x - (-16))

Simplifying:

y + 14 = (-7/8)(x + 16)

To get the desired equation in standard form, you can multiply both sides of the equation by 8 to clear the fraction:

8(y + 14) = -7(x + 16)

Expanding:

8y + 112 = -7x - 112

Arranging the terms to get the standard form:

7x + 8y = -224

Therefore, the equation of the line that passes through the point (−16,−14) with a slope of −7/8 is 7x + 8y = -224.