Consider the formula that relates distance, velocity, and time (d=vt). If you are interested in the time it takes for a ladybug traveling at a speed of 3 inches per second to crawl up a 10-foot section of wall, which unit conversion makes the most sense to use?(1 point)
Responses
Converting feet to inches by multiplying 11 feet by 1 foot12 inches.
Converting feet to inches by multiplying 11 feet by Start Fraction 1 foot over 12 inches End Fraction .
Converting feet to inches by dividing 10 feet by 12 inches1 foot.
Converting feet to inches by dividing 10 feet by Start Fraction 12 inches over 1 foot End Fraction .
Converting feet to inches by multiplying 10 feet by 12 inches1 foot.
Converting feet to inches by multiplying 10 feet by Start Fraction 12 inches over 1 foot End Fraction .
Converting feet to inches by multiplying 10 feet by 12.
Converting feet to inches by multiplying 10 feet by 12.
The correct answer is:
Converting feet to inches by multiplying 10 feet by 12 inches/foot.
The unit conversion that makes the most sense to use is: Converting feet to inches by multiplying 10 feet by 12 inches.
The correct unit conversion to use in this case is:
Converting feet to inches by multiplying 10 feet by 12 inches/foot.
To understand why this is the correct conversion, let's break it down:
The problem states that the ladybug is crawling up a 10-foot section of a wall. In order to calculate the time it takes for the ladybug to crawl this distance, we need to convert the distance from feet to inches. This is because the given velocity of the ladybug is in inches per second.
We know that 1 foot is equal to 12 inches. So, to convert 10 feet to inches, we can multiply 10 feet by the conversion factor, which is 12 inches/foot.
This conversion factor allows us to cancel out the unit of feet, leaving us with the distance in inches. Therefore, multiplying 10 feet by 12 inches/foot gives us the conversion from feet to inches.
Using this conversion, we can now use the formula d = vt, where d is the distance, v is the velocity, and t is the time, to calculate the time it takes for the ladybug to crawl the 10-foot section of the wall.