1+2+3+..............+100=

5050

To find the sum of the numbers from 1 to 100, you can use the formula for the sum of an arithmetic series, which is given by:

Sn = (n/2)(a + l)

Where:
- Sn is the sum of the series
- n is the number of terms
- a is the first term
- l is the last term

In this case, the first term (a) is 1, the last term (l) is 100, and there are 100 terms (n = 100).

Using the formula, the sum of the numbers from 1 to 100 is:

Sn = (100/2)(1 + 100)
= (50)(1 + 100)
= 50(101)
= 5050

Therefore, the sum of the numbers from 1 to 100 is 5050.

To find the sum of the consecutive integers from 1 to 100, you can use a formula or a mathematical approach.

One way to find the sum is by using the formula for the sum of an arithmetic series:

The sum of an arithmetic series can be calculated using the formula:

Sn = (n/2)(a + L)

where:
Sn is the sum of the series.
n is the number of terms in the series.
a is the first term.
L is the last term.

In this case, the first term (a) is 1, the last term (L) is 100, and there are 100 terms (n) in total.

Let's substitute these values into the formula:

S100 = (100/2)(1 + 100)

Now, simplify the equation:

S100 = (50)(101)
S100 = 5050

Therefore, the sum of the consecutive integers from 1 to 100 is 5050.