How many grams of magnesium chloride are in 75.0 mL of a 200 M solution of magnesium chloride in water? porbvide working out
To determine the number of grams of magnesium chloride in 75.0 mL of a 200 M solution, we need to use the equation:
Grams of solute = (Molarity of solution) x (Volume of solution in liters) x (Molar mass of solute)
Given:
Molarity of solution = 200 M
Volume of solution = 75.0 mL = 75.0/1000 L (since there are 1000 mL in 1 L)
To convert mL to L, we divide by 1000:
Volume of solution = 0.075 L
The molar mass of magnesium chloride (MgCl2) can be calculated using the atomic masses:
Molar mass = (mass of Mg) + 2 x (mass of Cl)
Mass of Mg = 24.31 g/mol (from periodic table)
Mass of Cl = 35.45 g/mol (from periodic table)
Molar mass of MgCl2 = 24.31 + 2 x 35.45 = 95.21 g/mol
Now we can substitute the given values into the equation:
Grams of solute = (200 M) x (0.075 L) x (95.21 g/mol)
By multiplying the values, we get:
Grams of solute = 1425.75 g
Therefore, there are 1425.75 grams of magnesium chloride in 75.0 mL of a 200 M solution.
To determine how many grams of magnesium chloride are in 75.0 mL of a 200 M solution, we need to calculate the moles of magnesium chloride first.
The formula to calculate moles is:
moles = concentration (M) x volume (L)
Given:
Concentration (M) = 200 M
Volume (L) = 75.0 mL = 0.075 L
Let's calculate the moles:
moles = 200 M x 0.075 L
moles = 15 mol
Now, to calculate the grams of magnesium chloride, we need to use the molar mass of magnesium chloride (MgCl₂), which is approximately 95.21 g/mol.
grams = moles x molar mass
grams = 15 mol x 95.21 g/mol
grams = 1428.15 g
Therefore, there are approximately 1428.15 grams of magnesium chloride in 75.0 mL of a 200 M solution.
To calculate the number of grams of magnesium chloride in a given volume of a solution, we need to use the formula:
grams of solute = (volume of solution in liters) x (molarity) x (molar mass of the solute)
First, we need to convert the volume of the solution from milliliters (mL) to liters (L). We can do this by dividing the volume by 1000, since 1 liter is equal to 1000 milliliters:
75.0 mL ÷ 1000 = 0.075 L
Now, we can use the molarity of the solution to find the number of moles of magnesium chloride. The molarity (M) of the solution means it contains 200 moles of magnesium chloride per liter of solution:
Moles of magnesium chloride = (volume of solution in liters) x (molarity)
Moles of magnesium chloride = 0.075 L x 200 M = 15 moles
Finally, we need to find the molar mass of magnesium chloride (MgCl2). The molar mass is the sum of the atomic masses of each element in the compound. Looking up the atomic masses of magnesium (Mg) and chlorine (Cl) in the periodic table, we find:
Magnesium (Mg) = 24.31 g/mol
Chlorine (Cl) = 35.45 g/mol
Molar mass of magnesium chloride (MgCl2) = (atomic mass of magnesium) + 2 x (atomic mass of chlorine)
Molar mass of magnesium chloride (MgCl2) = 24.31 g/mol + 2 x 35.45 g/mol = 95.21 g/mol
Finally, we can calculate the grams of magnesium chloride:
Grams of magnesium chloride = (moles of magnesium chloride) x (molar mass of magnesium chloride)
Grams of magnesium chloride = 15 moles x 95.21 g/mol = 1428.15 grams
Therefore, there are 1428.15 grams of magnesium chloride in 75.0 mL of a 200 M solution of magnesium chloride in water.