The concentration of a 100 mL solution of 10 g of Cu(OH)2 is:
To find the concentration of a solution, we need to know the amount of solute (in this case, Cu(OH)2) in the solution and the volume of the solution.
Given:
Amount of Cu(OH)2 = 10 g
Volume of solution = 100 mL
To find the concentration, we divide the amount of solute by the volume of the solution:
Concentration = Amount of solute / Volume of solution
First, we need to convert the volume of the solution to liters, since the concentration is typically expressed in moles per liter (M).
Volume of solution = 100 mL = 100/1000 L = 0.1 L
Now we can calculate the concentration:
Concentration = 10 g / 0.1 L = 100 g/L
Therefore, the concentration of the 100 mL solution of 10 g of Cu(OH)2 is 100 g/L.
To find the concentration of a solution, we need to know the amount of solute (in this case, Cu(OH)2) and the volume of the solution.
Given:
Amount of solute (Cu(OH)2): 10 g
Volume of solution: 100 mL
To find the concentration, we use the formula:
Concentration = Amount of Solute (in grams) / Volume of Solution (in liters)
First, we need to convert the volume from milliliters to liters:
Volume of Solution = 100 mL / 1000 mL/L
Volume of Solution = 0.1 L
Now, we can substitute the values into the formula:
Concentration = 10 g / 0.1 L
Concentration = 100 g/L
Therefore, the concentration of the 100 mL solution of 10 g of Cu(OH)2 is 100 g/L.
To find the concentration of a solution, we need to know the amount of solute (in grams) and the volume of the solution (in mL). In this case, the amount of solute is given as 10 g, and the volume of the solution is given as 100 mL.
To find the concentration, we first need to convert the volume from mL to liters, because concentration is typically expressed in terms of moles per liter (M).
Converting the volume from mL to liters:
100 mL = 100/1000 L = 0.1 L
Next, we need to find the number of moles of Cu(OH)2, which can be calculated using the molar mass. The molar mass of Cu(OH)2 can be calculated as follows:
Molar mass of Cu(OH)2 = (atomic mass of Cu * 1) + (atomic mass of O * 2) + (atomic mass of H * 2)
= (63.55 g/mol * 1) + (16.00 g/mol * 2) + (1.008 g/mol * 2)
= 63.55 g/mol + 32.00 g/mol + 2.016 g/mol
= 97.56 g/mol
Now, we can use the molar mass to calculate the number of moles of Cu(OH)2:
Number of moles = mass of Cu(OH)2 / molar mass of Cu(OH)2
= 10 g / 97.56 g/mol
≈ 0.1024 mol
Finally, we can calculate the concentration (C) using the formula:
C = number of moles / volume of solution
C = 0.1024 mol / 0.1 L
= 1.024 M
Therefore, the concentration of the 100 mL solution of 10 g of Cu(OH)2 is approximately 1.024 M.