lam a prime number.I am equal to the
sum ofther first six prime numbers. What
number am I?
The prime numbers are 2, 3, 5, 7, 11, 13. The sum of these numbers is 2 + 3 + 5 + 7 + 11 + 13 = 41. Therefore, the number you are is 41.
To find the prime number that is equal to the sum of the first six prime numbers, we need to calculate the sum of the first six primes and check if the sum is a prime number.
The first six prime numbers are: 2, 3, 5, 7, 11, and 13.
Adding these numbers together:
2 + 3 + 5 + 7 + 11 + 13 = 41
So the prime number that is equal to the sum of the first six prime numbers is 41.
To find the number that satisfies the given conditions, we need to find the sum of the first six prime numbers and check if any of those sums are prime numbers.
Let's list the first six prime numbers:
2, 3, 5, 7, 11, 13
Now, let's calculate their sum:
2 + 3 + 5 + 7 + 11 + 13 = 41
Therefore, the sum of the first six prime numbers is 41. To check if 41 is a prime number, we can divide it by all the numbers less than its square root (rounded up) and see if any of the divisions result in a remainder of 0.
Checking the divisibility of 41:
Given that the square root of 41 is approximately 6.4, we only need to check divisibility by the prime numbers less than or equal to 6: 2, 3, 5
41 ÷ 2 = 20 remainder 1
41 ÷ 3 = 13 remainder 2
41 ÷ 5 = 8 remainder 1
Since 41 is not divisible by any of the prime numbers less than or equal to 6, it does not have any divisors other than 1 and itself. Therefore, 41 is a prime number.
Hence, the number you are is 41.