`5x^{2}+2y` when x =-3 and y=20
To evaluate `5x^{2}+2y` when `x = -3` and `y = 20`, substitute these values into the expression:
`= 5(-3)^{2} + 2(20)`
`= 5(9) + 40`
`= 45 + 40`
`= 85`
Therefore, `5x^{2}+2y` when `x = -3` and `y = 20` is equal to 85.
Evaluate the expression `\frac{9mn}{-2p}` when `m\ =\ \frac{1}{3},` `n\ =-2,`and `p=5.` Type your fractional answer below.
To evaluate the expression `\frac{9mn}{-2p}` when `m = \frac{1}{3},` `n = -2`, and `p = 5`, substitute these values into the expression:
`\frac{9mn}{-2p} = \frac{9 \cdot \left(\frac{1}{3}\right) \cdot (-2)}{-2 \cdot 5}`
`= \frac{9 \cdot \frac{-2}{3}}{-10}`
`= \frac{-18}{-10}`
This can be simplified by dividing both the numerator and the denominator by the greatest common divisor (GCD) of 18 and 10, which is 2.
`= \frac{-9}{-5}`
Therefore, the simplified expression `\frac{9mn}{-2p}` when `m = \frac{1}{3},` `n = -2`, and `p = 5` is equal to `\frac{9}{5}`.
To find the value of `5x^2 + 2y` when `x = -3` and `y = 20`, we substitute these values into the expression and simplify.
Substituting `x = -3` and `y = 20`:
= `5(-3^2) + 2(20)` (Replace `x` with `-3` and `y` with `20`)
= `5(9) + 2(20)` (Simplify `-3^2` to `9`)
= `45 + 40` (Multiply `5` by `9` and `2` by `20`)
= `85` (Add `45` and `40`)
Therefore, `5x^2 + 2y`, when `x = -3` and `y = 20`, is equal to `85`.