Select the choice that indicates AB←→ is the perpendicular bisector of CD←→ if they intersect at P.(1 point)

Responses

AC¯¯¯¯¯¯¯¯⊥BD¯¯¯¯¯¯¯¯ and AP¯¯¯¯¯¯¯¯≅BP¯¯¯¯¯¯¯¯
Modifying above upper A upper C with bar perpendicular to Modifying above upper B upper D with bar and Modifying above upper A upper P with bar congruent to Modifying above upper B upper P with bar

CD¯¯¯¯¯¯¯¯⊥AB¯¯¯¯¯¯¯¯
Modifying above upper C upper D with bar perpendicular to Modifying above upper A upper B with bar

AP¯¯¯¯¯¯¯¯≅BP¯¯¯¯¯¯¯¯
Modifying above upper A upper P with bar congruent to Modifying above upper B upper P with bar

AB¯¯¯¯¯¯¯¯⊥CD¯¯¯¯¯¯¯¯ and CP¯¯¯¯¯¯¯¯≅DP¯¯¯¯¯¯¯¯

The correct choice is:

AB¯¯¯¯¯¯¯¯⊥CD¯¯¯¯¯¯¯¯ and CP¯¯¯¯¯¯¯¯≅DP¯¯¯¯¯¯¯¯

The correct choice is "Modifying above A with bar P congruent to B with bar P." This indicates that AP¯¯¯¯¯¯¯¯≅BP¯¯¯¯¯¯¯¯, meaning that the line segments AP and BP are congruent. This is a characteristic of a perpendicular bisector.