Which sentence below includes a compound verb?
(1 point)
Responses
The wolf pounced on a mouse and ate it.
The wolf pounced on a mouse and ate it.
The wolf’s underfur grew dense and thick.
The wolf’s underfur grew dense and thick.
Hares and caribou are among the wolf’s prey.
The wolf pounced on a mouse and ate it.
Solve for p.
3(p + q) = p
(1 point)
Responses
q = –two-thirdsp
q = – Image with alt text: two-thirds p
q = –start fraction three over two end fractionp
q = – Image with alt text: start fraction three over two end fraction p
p = –two-thirdsq
p = – Image with alt text: two-thirds q
p = –start fraction three over two end fractionq
p = –start fraction three over two end fractionq
Solve for b, then find the value of b when a = 3.
4a = 2b − 7
(1 point)
Responses
–nine-halves
– Image with alt text: nine-halves
five-halves
Image with alt text: five-halves
nineteen-halves
Image with alt text: nineteen-halves
17
To solve for b, we need to isolate b in the equation 4a = 2b - 7.
4a + 7 = 2b
Divide both sides by 2:
(4a + 7)/2 = b
2a + 7/2 = b
Now we can substitute a = 3 into the equation to find the value of b:
2(3) + 7/2 = b
6 + 7/2 = b
12/2 + 7/2 = b
19/2 = b
The value of b when a = 3 is nineteen-halves.
Solve for r.
d = rt
(1 point)
Responses
r = dt
r = dt
r equals t over d
Image with alt text: r equals t over d
r equals d over t
Image with alt text: r equals d over t
r equals d minus t
r = d over t
Find the width of a rectangle with a perimeter of 90 and a length of 15.
(1 point)
Responses
90
90
15
15
45
45
30
To find the width of the rectangle, we need to use the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
Given that the length is 15 and the perimeter is 90, we can substitute these values into the formula:
90 = 2(15) + 2w
90 = 30 + 2w
60 = 2w
w = 60/2
w = 30
Therefore, the width of the rectangle is 30.