Rubidium has an atomic number of 37 and a mass number of 85. How many protons, neutrons, and electrons does an ion of rubidium with a 1+ charge have?(1 point)
Responses
37 protons, 48 neutrons, and 38 electrons
37 protons, 48 neutrons, and 38 electrons
48 protons, 37 neutrons, and 36 electrons
48 protons, 37 neutrons, and 36 electrons
37 protons, 48 neutrons, and 36 electrons
37 protons, 48 neutrons, and 36 electrons
48 protons, 37 neutrons, and 38 electrons
48 protons, 37 neutrons, and 38 electrons
The correct answer is: 37 protons, 48 neutrons, and 36 electrons
If an ion of rubidium has a 1+ charge, it means that it has lost one electron.
The atomic number of rubidium is 37, which means it normally has 37 protons. Since the ion has a 1+ charge, it now has one less electron, so it has 36 electrons.
The mass number of rubidium is 85, which includes the sum of protons and neutrons. Since we know it has 37 protons, we can subtract that from the mass number to find the number of neutrons.
Mass number - Number of protons = Number of neutrons
85 - 37 = 48 neutrons
Therefore, an ion of rubidium with a 1+ charge has 37 protons, 48 neutrons, and 36 electrons.