Graph the linear equation y= -3x+2

To graph the linear equation y = -3x + 2, we can plot a few points and draw a line through them.

Let's choose some values for x and find the corresponding y values:

When x = 0, y = -3(0) + 2 = 2. So we have the point (0, 2).
When x = 1, y = -3(1) + 2 = -1. So we have the point (1, -1).
When x = -1, y = -3(-1) + 2 = 5. So we have the point (-1, 5).

Plotting these points on a graph and connecting them with a line, we get a straight line that extends infinitely in both directions.

Here is the graph:
graph{y = -3x+2 [-10, 10, -5, 5]}

To graph the linear equation y = -3x + 2, we can start by plotting a few points and then connecting them to form a line.

Let's choose some values for x and find the corresponding y values:

When x = 0:
y = -3(0) + 2
= 0 + 2
= 2
So, we have the point (0, 2).

When x = 1:
y = -3(1) + 2
= -3 + 2
= -1
So, we have the point (1, -1).

When x = -1:
y = -3(-1) + 2
= 3 + 2
= 1
So, we have the point (-1, 1).

Now, we can plot these points on a coordinate plane and connect them with a line:

-3 | .
-2 | .
-1 | .
0 | .
1 | .
2 | .
--------------

As you can see, the line passes through the points (0, 2), (1, -1), and (-1, 1).