Swimming Pool On a certain hot summer's day, 471 people used the public swimming pool. The daily prices are $1.25 for children and $2.25 for adults. The receipts for
admission totaled $860.75. How many children and how many adults swam at the public pool that day?
Let x be the number of children and y be the number of adults who swam at the public pool.
We know that x + y = 471 and 1.25x + 2.25y = 860.75.
To solve the equations, we can use substitution or elimination method. Let's use substitution:
Rearranging the first equation, we have x = 471 - y.
Substituting this into the second equation, we get 1.25(471 - y) + 2.25y = 860.75.
Expanding the equation, we get 588.75 - 1.25y + 2.25y = 860.75.
Combining like terms, we get 1.00y = 860.75 - 588.75.
Simplifying the right side, we get 1.00y = 272.
Dividing both sides by 1.00, we get y = 272.
Substituting this value back into the first equation, we get x + 272 = 471.
Subtracting 272 from both sides, we get x = 199.
Therefore, there were 199 children and 272 adults who swam at the public pool that day.
Let's assume the number of children who swam at the pool as "x" and the number of adults as "y".
According to the problem, the total number of people who swam at the pool is 471, so we have the equation:
x + y = 471 (Equation 1)
The receipt from the admission totaled $860.75, so the total value of children's tickets and adults' tickets is $860.75.
The cost of one child's ticket is $1.25, so the total value of children's tickets is 1.25x.
The cost of one adult's ticket is $2.25, so the total value of adults' tickets is 2.25y.
According to the problem, the sum of the total value of children's tickets and adults' tickets is $860.75, so we have the equation:
1.25x + 2.25y = 860.75 (Equation 2)
Now we have a system of equations with Equation 1 and Equation 2.
We can solve this system of equations to find the values of x and y.