What is the equation of the solution of HCl and sodium tetraborate
The equation for the reaction between HCl (hydrochloric acid) and sodium tetraborate can be written as follows:
HCl + Na2B4O7 -> NaCl + H3BO3
This reaction produces sodium chloride (NaCl) and boric acid (H3BO3) as products.
The chemical equation for the reaction between hydrochloric acid (HCl) and sodium tetraborate can be written as follows:
2 HCl + Na2B4O7 → 4 H3BO3 + 2 NaCl
In this reaction, hydrochloric acid (HCl) reacts with sodium tetraborate (Na2B4O7), also known as borax, to produce boric acid (H3BO3) and sodium chloride (NaCl). The reaction is balanced with 2 moles of hydrochloric acid combining with 1 mole of sodium tetraborate to form 4 moles of boric acid and 2 moles of sodium chloride.