What is the slope and the y-intercept of the equation 9+27/2 x=−3/2 y. Write the y-intercept as an ordered pair.(1 point)
To find the slope and the y-intercept of the equation 9+27/2x=−3/2y, we need to rewrite the equation in the form y = mx + b, where m represents the slope and b represents the y-intercept.
Starting with the given equation:
9 + 27/2x = -3/2y
Multiply both sides by -2/3 to isolate y:
(9 + 27/2x)(-2/3) = y
Simplify:
-6 - 18x = y
Now we have the equation in the form y = mx + b:
y = -18x - 6
From this equation, we can determine that the slope (m) is -18 and the y-intercept (b) is -6.
The y-intercept can be written as an ordered pair (0, -6).
To find the slope and the y-intercept of the equation 9 + 27/2x = -3/2y, we need to rewrite the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
1. Start by rearranging the equation to isolate y:
9 + 27/2x = -3/2y
Divide both sides of the equation by -3/2:
(9 + 27/2x) / (-3/2) = y
(9 + 27/2x) * (-2/3) = y
Simplifying the equation:
y = (-2/3)(9 + 27/2x)
y = (-2/3)(9) + (-2/3)(27/2x)
y = -6 + (-9x)
2. The equation is now in slope-intercept form (y = -9x - 6).
The slope (m) is -9, and the y-intercept (b) is -6.
Therefore, the slope is -9 and the y-intercept is (-6, 0).