26 + 6b ≥ 2(3b + 4)
To solve the inequality 26 + 6b ≥ 2(3b + 4), we can simplify it step by step.
First, we can distribute the 2 on the right side: 26 + 6b ≥ 6b + 8.
Next, we can simplify by subtracting 6b from both sides: 26 ≥ 8.
Finally, we can subtract 8 from both sides: 18 ≥ 0.
Therefore, the solution to the inequality is 18 ≥ 0, which is always true. This means that any value of b will satisfy the original inequality.
To solve the inequality 26 + 6b ≥ 2(3b + 4), follow these steps:
1. Distribute the 2 on the right side of the inequality:
26 + 6b ≥ 6b + 8
2. Combine like terms:
6b - 6b + 26 ≥ 6b - 6b + 8
26 ≥ 8
3. Since 26 is greater than or equal to 8, the inequality is always true for any value of b. Therefore, the solution is all real numbers.