A car’s engine provides a forward force of 2000 N while the force of air resistance is 800 N in the opposite direction. With what force will the car move, and in which direction?(1 point)
Responses
1200 N forward
1200 N forward
2800 N forward
2800 N forward
1200 N backward
1200 N backward
16000 N forward
The force with which the car will move can be calculated by subtracting the force of air resistance from the forward force provided by the engine:
Force of movement = Forward force - Force of air resistance
Force of movement = 2000 N - 800 N
Force of movement = 1200 N forward
Therefore, the car will move with a force of 1200 N in the forward direction.
The correct response is: 1200 N forward
Two movers are attempting to push a couch up a ramp. One mover applies a force of 80 N to the right, but the force of friction between the couch and the ramp is providing a force of 110 N in the opposite direction, and the couch slides down the ramp.
At minimum, how much force will the second mover need to apply to help push the couch up the ramp?
(1 point)
Responses
30 N
30 N
31 N
31 N
110 N
110 N
80 N
To push the couch up the ramp, the combined force applied by both movers needs to be greater than the force of friction between the couch and the ramp. In this case, the force of friction is 110 N in the opposite direction.
The first mover is applying a force of 80 N to the right. To determine the minimum force the second mover needs to apply, subtract the force of friction from the force applied by the first mover:
Minimum force by the second mover = Force of friction - Force applied by the first mover
Minimum force by the second mover = 110 N - 80 N
Minimum force by the second mover = 30 N
Therefore, the second mover needs to apply a minimum force of 30 N to help push the couch up the ramp.
The correct response is: 30 N
Newton's Laws Unit Test
3 of 153 of 15 Items
Question
A group of students conduct an experiment to study Newton’s second law of motion. They applied a force to a toy car and measure its acceleration. The table shows the results.
Force (N) Acceleration (m/s²)
2.0 5.0
3.0 7.5
6.0 15.0
If the students graph the data points, which conclusion will they be able to make?
(1 point)
Responses
The data points will fall along a line. This shows that as the force increases, the acceleration decreases.
The data points will fall along a line. This shows that as the force increases, the acceleration decreases.
The data points will not fall along a line. This shows that as the force increases, the acceleration decreases.
The data points will not fall along a line. This shows that as the force increases, the acceleration decreases.
The data points will fall along a line. This shows that as the force increases, the acceleration increases.
The data points will fall along a line. This shows that as the force increases, the acceleration increases.
The data points will not fall along a line. This shows that as the force increases, the acceleration increases.
To determine the conclusion, let's analyze the given data points for force and acceleration:
Force (N) | Acceleration (m/s²)
2.0 | 5.0
3.0 | 7.5
6.0 | 15.0
If we plot these data points on a graph, we can see that as the force increases, the acceleration also increases. The relationship between force and acceleration is directly proportional.
Therefore, the correct conclusion is:
"The data points will fall along a line. This shows that as the force increases, the acceleration increases."
The correct response is: The data points will fall along a line. This shows that as the force increases, the acceleration increases.
Use the image to answer the question below.
In the experimental setup shown, a car has one end of a string attached to it, and the other end is attached to a fixed number of metal discs. The car moves along the table and two probes sense the motion of the car. The probes send information to a computer that displays the acceleration and velocity of the experiment. When looking at these results, which quantity stays constant during the trials?
Without the image, it is not possible to determine which quantity stays constant during the trials. Please provide a description or more information about the image, and I will be happy to help answer your question.
Use the image to answer the question below.
In the experimental setup shown, a car has one end of a string attached to it, and the other end is attached to a fixed number of metal discs. The car moves along the table and two probes sense the motion of the car. The probes send information to a computer that displays the acceleration and velocity of the experiment. When looking at these results, which quantity stays constant during the trials?
A car at the one end of the table is tied to a hanger at the other end of the table using a string and a pully. The hanger is hanging over the side of the table while the car is placed flat on the surface of the table. The hanger can support the metal discs. A ruler, a laptop, and other equipment are also placed on the table.
(1 point)
Responses
mass
mass
velocity
velocity
force
force
acceleration
acceleration
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Use the image to answer the question below.
In the experimental setup shown, a car has one end of a string attached to it, and the other end is attached to a fixed number of metal discs. The car moves along the table and two probes sense the motion of the car. The probes send information to a computer that displays the acceleration and velocity of the experiment. When looking at these results, which quantity stays constant during the trials?
A car at the one end of the table is tied to a hanger at the other end of the table using a string and a pully. The hanger is hanging over the side of the table while the car is placed flat on the surface of the table. The hanger can support the metal discs. A ruler, a laptop, and other equipment are also placed on the table.
(1 point)
Responses
mass
mass
velocity
velocity
force
force
acceleration
acceleration
Skip to navigation
Based on the description of the experimental setup, the quantity that stays constant during the trials is the mass. This is because the car has one end of the string attached to it, and the other end is attached to a fixed number of metal discs. The mass of the car and the fixed number of metal discs remains constant throughout the trials, while other quantities like acceleration and velocity may change depending on the forces applied.
Therefore, the correct response is: mass
To determine the net force acting on the car and its direction, we need to find the difference between the forward force provided by the engine and the opposing force of air resistance.
Given:
Forward force provided by the engine = 2000 N
Force of air resistance = 800 N
To find the net force, subtract the force of air resistance from the forward force:
Net force = Forward force - Force of air resistance
= 2000 N - 800 N
= 1200 N
Therefore, the car will move with a net force of 1200 N in the forward direction, as indicated by the first option: 1200 N forward.