A current-carrying wire is oriented at right angles to a uniform magnetic field. If the length of the wire is
0.50 m and it experiences a force of 0.90 N while carrying a current of 4.0 A, what is the strength of the magnetic field?

I did the work and got:
0.45 ...???

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  1. In this situation,

    F = B I L

    where L is the length of the wire.


    B = F/(IL)

    You got the correct number. The units are Teslas (T)

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  2. yes, 0.45 T thanks for checking!

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