At what frequency would a 0•5H inductor have a reactance of 1000 ohms
The reactance of an inductor is given by the formula Xl = 2pi*f*L, where Xl is the reactance in ohms, f is the frequency in hertz, and L is the inductance in henries.
In this case, we have Xl = 1000 ohms and L = 0.5 H.
Substituting these values into the formula, we get:
1000 = 2pi*f*0.5
Simplifying the equation, we have:
f = 1000 / (2pi*0.5)
f = 1000 / pi
Therefore, the frequency at which a 0.5H inductor would have a reactance of 1000 ohms is approximately 318.31 Hz (rounded to two decimal places).
The reactance of an inductor is given by the formula Xl = 2πfL, where Xl is the reactance, f is the frequency, and L is the inductance.
In this case, we have Xl = 1000 ohms and L = 0.5 H. Plugging these values into the formula, we can solve for the frequency f.
1000 = 2πf(0.5)
Dividing both sides of the equation by 0.5, we get:
2000 = 2πf
Dividing both sides of the equation by 2π, we have:
f = 2000 / (2π)
Using a calculator, we can determine the value:
f ≈ 318.3 Hz
Therefore, a 0.5H inductor would have a reactance of 1000 ohms at a frequency of approximately 318.3 Hz.