Use the chemical reaction to answer the question.
CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?
The chemical reaction shows that the reaction of 1 mole of calcium carbonate (CaCO3) produces 1 mole of carbon dioxide (CO2) and 1 mole of calcium oxide (CaO).
To determine the total mass of the products, we need to calculate the molar masses of carbon dioxide and calcium oxide.
Molar mass of CO2 = 12.01 g/mol (C) + 2 * 16.00 g/mol (O) = 44.01 g/mol
Molar mass of CaO = 40.08 g/mol (Ca) + 16.00 g/mol (O) = 56.08 g/mol
Since the molar ratio is 1:1 for both CO2 and CaO, the total mass of the products will be equal to the molar mass of CO2 plus the molar mass of CaO.
Total mass of the products = Molar mass of CO2 + Molar mass of CaO
= 44.01 g/mol + 56.08 g/mol
= 100.09 g/mol
Therefore, the total mass of the products is 100.09 grams.
To find the total mass of the products in the chemical reaction, we need to calculate the molar mass of each product and multiply it by the stoichiometric coefficient.
The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.
The molar mass of calcium oxide (CaO) is approximately 56.08 g/mol.
Looking at the balanced chemical equation:
1 mol of CaCO3 produces 1 mol of CO2 and 1 mol of CaO.
Since the molar mass of CaCO3 is 100.09 g/mol (using the atomic masses: Ca = 40.08 g/mol, C = 12.01 g/mol, and O = 16.00 g/mol), we can calculate the moles of CaCO3 in 30 grams:
Number of moles = mass / molar mass
Number of moles of CaCO3 = 30 g / 100.09 g/mol = 0.2998 mol (approximately 0.3 mol)
Since the molar ratio between CaCO3 and CO2 is 1:1, the number of moles of CO2 produced is also approximately 0.3 mol.
Similarly, since the molar ratio between CaCO3 and CaO is 1:1, the number of moles of CaO produced is approximately 0.3 mol.
Finally, to find the total mass of the products, we multiply the number of moles by their respective molar masses and add them together:
Total mass of products = (0.3 mol CO2) * (44.01 g/mol) + (0.3 mol CaO) * (56.08 g/mol)
Total mass of products = 13.20 g + 16.82 g
Total mass of products = 29.02 g
Therefore, the total mass of the products in the chemical reaction is approximately 29.02 grams.