Point Q'is the image of Q (0,6) under the translation (x,y) (x+7, y-5)
To find the image of a point under a translation, we need to apply the translation rule to the given point.
Applying the translation rule (x, y) → (x + 7, y - 5) to the point Q (0, 6), we get:
Q' = (0 + 7, 6 - 5)
= (7, 1)
Therefore, the image of point Q (0, 6) under the translation (x, y) → (x + 7, y - 5) is Q' (7, 1).
To find the image of point Q(0,6) under the translation (x,y) -> (x+7, y-5), we can apply the translation rules to each coordinate separately.
For the x-coordinate, add 7 to the x-coordinate of point Q:
x-coordinate of Q' = 0 + 7 = 7
For the y-coordinate, subtract 5 from the y-coordinate of point Q:
y-coordinate of Q' = 6 - 5 = 1
Therefore, the image point Q' of point Q(0,6) under the translation (x,y) -> (x+7, y-5) is Q'(7,1).