A water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days?
A. -80 gallons
B. -480 gallons
C. 480 gallons
D. 80 gallons
The water tank decreases by 10 gallons every 3 hours, so it decreases by 10/3 = <<10/3=3.3333333333333335>>3.33 gallons every hour.
In one day, which has 24 hours, the water tank decreases by 24*3.33 = <<24*3.33=79.92>>79.92 gallons.
So after six days, the water tank will decrease by 6*79.92 = 479.52 gallons.
The total change in the amount of water in the tank after 6 days is -479.52 gallons, which is approximately equal to -480 gallons.
Therefore, the correct answer is B. -480 gallons.
To find the total change in the amount of water in the tank after 6 days, we need to calculate the change each day and then multiply it by the number of days.
First, let's find the change in the amount of water in the tank per day:
10 gallons decrease every 3 hours
We need to convert this to per day, so:
Number of 3-hour periods in a day = 24/3 = 8
Change in gallons per day = 10 gallons * 8 periods = 80 gallons
Now, let's calculate the total change in the amount of water after 6 days:
Total change in gallons = Change per day * Number of days
Total change in gallons = 80 gallons * 6 days = 480 gallons
Therefore, the total change in the amount of water in the tank after 6 days is 480 gallons. The answer is option C. 480 gallons.