Electrostatic force F exists between two point charges. If the both charges are doubled, the force between the charges will be
F
4 F
2 F
F/4
According to Coulomb's law, the electrostatic force (F) between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Let's assume the original charges are q1 and q2, and the force between them is F. If both charges are doubled (2q1 and 2q2), the force between them can be calculated.
Using Coulomb's law:
F_new = k * (2q1) * (2q2) / r^2
= (4 * k * q1 * q2) / r^2
= 4 * (k * q1 * q2) / r^2
= 4F
Therefore, the force between the charges will be 4F when both charges are doubled.
The force between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
Let's denote the original charges as q1 and q2, and the original force as F.
If both charges are doubled (2q1 and 2q2), the new force between them (F') can be calculated using the formula for electric force:
F' = k * (2q1) * (2q2) / r^2
Since q1 and q2 are both doubled, the equation becomes:
F' = k * 4q1 * 4q2 / r^2
Simplifying the equation:
F' = (4 * 4) * (k * q1 * q2 / r^2)
F' = 16 * (k * q1 * q2 / r^2)
We can see that the new force is 16 times the original force (F). Therefore, the force between the charges will be 16F.