Solve this equation for y: y3=2x(1 point)
Responses
y=2x+3y is equal to 2 x plus 3
y=23xy is equal to 2 thirds x
y=6xy is equal to 6 x
y=2x−3
To solve the equation y^3 = 2x for y, we need to take the cube root of both sides.
∛(y^3) = ∛(2x)
Simplifying,
y = ∛(2x)
Therefore, the solution is y = ∛(2x).
Solve this equation for y: y/3=2x
Responses
y=2x+3y is equal to 2 x plus 3
y=23xy is equal to 2 thirds x
y=6xy is equal to 6 x
y=2x−3
To solve the equation y/3 = 2x for y, we need to isolate y by getting rid of the division by 3.
To do this, we can multiply both sides of the equation by 3.
3(y/3) = 3(2x)
Simplifying,
y = 6x
Therefore, the solution is y = 6x.
5. Over the summer, you text a bunch. Let’s say you make 50 texts every 2 days.
The graph represents the scenario.
(4 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Fill in the missing parts of the table:
x - # of days 0 a. 7 b.
y - # of texts c. 75 d. 300
a. Response area
b. Response area
c. Response area
d. Response area
Based on the information given, we know that you make 50 texts every 2 days.
Using this, we can fill in the missing parts of the table as follows:
x - # of days 0 a. 7 b. c. d.
y - # of texts b. c. d. 300
Since we make 50 texts every 2 days, we can calculate the number of texts for each value of x:
For x = 0 days, we haven't made any texts yet, so y = 0.
For x = 7 days, we can divide 7 by 2 to find the number of 2-day periods that have passed since the start (7/2 = 3.5). Since we only count complete 2-day periods, this means that we have made 3 complete sets of 50 texts, or 150 texts in total. So, y = 150.
For x = b, we don't have enough information to determine the number of texts made. This is a missing value in the table.
For x = c, we can count the number of 2-day periods that have passed since the start, which is equal to c/2. Since we make 50 texts every 2 days, the number of texts made will be 50 times the number of 2-day periods. So, y = 50(c/2) = 25c.
For x = d, we can calculate the number of 2-day periods that have passed since the start, which is equal to d/2. Again, we multiply this number by 50 to find the number of texts made. So, y = 50(d/2) = 25d.
Using this information, we can fill in the missing parts of the table:
x - # of days 0 a. 7 b.
y - # of texts 0 b. 150 d. 300
a. Response area: 0
b. Response area: 150
c. Response area: 75
d. Response area: 300
To solve the equation y^3 = 2x for y, you can take the cube root of both sides:
∛(y^3) = ∛(2x)
This simplifies to:
y = ∛(2x)
To solve the equation y^3 = 2x for y, we need to isolate y on one side of the equation. Here's how you can do it:
1. Start by taking the cube root of both sides of the equation to get rid of the exponent:
∛(y^3) = ∛(2x)
2. The cube root of y^3 is simply y, so we have:
y = ∛(2x)
Therefore, the solution to the equation y^3 = 2x for y is y = ∛(2x), where ∛ denotes the cube root.