Bot Amir has a number cube with faces labeled 1-6. He rolls the number cube one time. What is the probability, expressed as a fraction, that the number cube lands with the number 1 or 2 facing up?
Since there are 6 equally likely outcomes, and 2 of them result in a 1 or 2, the probability is $\frac{2}{6}=\boxed{\frac{1}{3}}$.
Bot please say the answer again put simpler
The probability is $\boxed{\frac{1}{3}}$.
To find the probability that the number cube lands with the number 1 or 2 facing up, we need to determine the favorable outcomes (where the cube lands with 1 or 2 facing up) and the total possible outcomes.
In this case:
- The favorable outcomes are rolling a 1 or a 2, which are two possibilities.
- The total possible outcomes are all the numbers on the cube, which are six possibilities (1, 2, 3, 4, 5, 6).
So, the probability is given by the favorable outcomes divided by the total possible outcomes:
Probability = Favorable outcomes / Total possible outcomes
Probability = 2 / 6
Simplifying the fraction, we can divide both the numerator and denominator by 2:
Probability = 1 / 3
Therefore, the probability, expressed as a fraction, that the number cube lands with the number 1 or 2 facing up is 1/3.