The chemist measures the volume of the unknown liquid as 1132 cm^3 and the mass of unknown liquid as 1.43kg
Pentane 0.63g/mL
Methyl acetate 0.93g/mL
Glycerol 1.3 g/mL
Ethanolamine 1.0g/mL
Acetone 0.79g/mL
Caluculate the density of liquid be sure your answer has the correct number of significant digits
Given the data is it possible to identify the liquid
If it is possible to identify the liquid what is it
To calculate the density of the liquid, we need to divide the mass of the liquid by its volume:
Density = Mass / Volume
Given:
Volume = 1132 cm^3 = 1132 mL
Mass = 1.43 kg = 1430 g
Density = 1430 g / 1132 mL = 1.264 g/mL
This value has 4 significant digits.
To identify the liquid, we compare the calculated density with the given densities of the substances:
Pentane: 0.63 g/mL
Methyl acetate: 0.93 g/mL
Glycerol: 1.3 g/mL
Ethanolamine: 1.0 g/mL
Acetone: 0.79 g/mL
Based on the calculated density of 1.264 g/mL, it is closest to the density of glycerol (1.3 g/mL). Therefore, the unknown liquid is most likely glycerol.
To calculate the density of the liquid, we need to divide the mass of the liquid by its volume.
Given:
Volume of liquid = 1132 cm^3
Mass of liquid = 1.43 kg
Density = Mass / Volume
Converting the volume to liters:
Volume = 1132 cm^3 / 1000 = 1.132 L
Density = 1.43 kg / 1.132 L
Using the appropriate number of significant figures for the density, we find:
Density = 1.26 kg/L
To identify the liquid, we can compare the calculated density to the densities of the provided liquids.
The closest density to 1.26 kg/L is glycerol with a density of 1.3 g/mL (or equivalently 1.3 kg/L). Therefore, the unknown liquid is most likely glycerol.