How many significant digits
8.3* 10 to power of-1 mL
11500kg
0.006100J
-6.0* 10 to power of-2 kJmol
The number of significant digits in each value is as follows:
8.3*10^-1 mL: 2 significant digits (8 and 3)
11500 kg: 4 significant digits (1, 1, 5, and 0)
0.006100 J: 4 significant digits (6, 1, 0, and 0)
-6.0*10^-2 kJ/mol: 2 significant digits (6 and 0)
To determine the number of significant digits in each given number, we need to count all the digits excluding leading and trailing zeros.
1. 8.3 × 10^-1 mL:
- The number 8.3 has two significant digits.
- The exponent -1 does not affect the significant digits.
Therefore, there are two significant digits in 8.3 × 10^-1 mL.
2. 11500 kg:
- The number 11500 has five significant digits.
- The trailing zeros after the decimal point are significant.
Therefore, there are five significant digits in 11500 kg.
3. 0.006100 J:
- The number 0.006100 has four significant digits.
- The leading zeros before the decimal point are not significant.
Therefore, there are four significant digits in 0.006100 J.
4. -6.0 × 10^-2 kJmol:
- The number -6.0 has two significant digits.
- The exponent -2 does not affect the significant digits.
Therefore, there are two significant digits in -6.0 × 10^-2 kJmol.
Summary:
1. 8.3 × 10^-1 mL has 2 significant digits.
2. 11500 kg has 5 significant digits.
3. 0.006100 J has 4 significant digits.
4. -6.0 × 10^-2 kJmol has 2 significant digits.